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Contact [7]
3 years ago
15

Need help from 7-9 pls

Mathematics
1 answer:
expeople1 [14]3 years ago
5 0

Answer:

b 5 a 6 b 7

Step-by-step explanation:

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How does a digit in the 10,000s place compare to a digit in the thousands place?
Delvig [45]
While a digit in the thousands place has a value 1,000 times the value of the digit. So to compare you can do 10,000 / 1,000 = 10, which means that a digit in the ten thousand place values ten times what the same digit values is it is the thousand place.
4 0
3 years ago
Ski rentals are $100 plus $18 per hour, as shown in the table above.
lisabon 2012 [21]

Answer:

1. f(x)=18X +100

2:108

3. 7.5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Alvin's age is two times Elga's age. The sum of their ages is 63. What is Elga's age?
lawyer [7]

Answer: Alvin = 42 yrs , Elga = 21 yrs

Step-by-step explanation:

Let Elga's age be x , and Alvin's age be y ,since Alvin is two times Elga's age , then

Alvin's age = 2x , that is

y = 2x ............... equation 1

The sum of their ages is 63 implies

x + y = 63 .............. equation 2

Solving the resulting linear equations by substitution method.

Substitute equation 1 into equation 2 , we have

x + 2x = 63

3x = 63

x = 63/3

x = 21

Therefore : Elga is 21 years old , then Alvin will be 21 x 2, which will be 42

8 0
3 years ago
What is the domain and range of the graph?
I am Lyosha [343]

Answer:5/8

Step-by-step explanation:

I just need more Brainly points

7 0
3 years ago
Find the approximate area between the curve f(x) = -4x² + 32x and on the x-axis on the interval [0,8] using 4 rectangles. Use th
Doss [256]

Split up the interval [0, 8] into 4 equally spaced subintervals:

[0, 2], [2, 4], [4, 6], [6, 8]

Take the right endpoints, which form the arithmetic sequence

r_i=2+\dfrac{8-0}4(i-1)=2i

where 1 ≤ <em>i</em> ≤ 4.

Find the values of the function at these endpoints:

f(r_i)=-4{r_i}^2+32r_i=-16i^2+64i

The area is given approximately by the Riemann sum,

\displaystyle\int_0^8f(x)\,\mathrm dx\approx\sum_{i=1}^4f(r_i)\Delta x_i

where \Delta x_i=\frac{8-0}4=2; so the area is approximately

\displaystyle2\sum_{i=1}^4(-16i^2+64i)=-32\sum_{i=1}^4i^2+128\sum_{i=1}^4i=-32\cdot\frac{4\cdot5\cdot9}6+128\cdot\frac{4\cdot5}2=\boxed{320}

where we use the formulas,

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6

6 0
3 years ago
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