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3 years ago

Pls help me I need these done

Mathematics

1 answer:

Tomtit [17]3 years ago

6 0

Answer:

the area of the square is 148.48 yd

the perimeter of the square is 48.8 yd

the area of the rectangle is 0.48 m

the perimeter of the rectangle is 2.8 m

Step-by-step explanation:

Area = l*w

12.2 * 12.2 = 148.48

12.2 + 12.2 + 12.2 + 12.2= 48.8

0.8 * 0.6 = 0.48

0.8 + 0.8 + 0.6 + 0.6 = 2.8

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Use Wolframalpha to find the exact volume of the solid obtained by rotating about x = [pi]/2 the region bounded by y = sin^2x, y

Alex777 [14]

Answer:

Step-by-step explanation:

Here the region between two curves is rotated about a vertical line.

The functions are

$y = sin^2x, \\y = sin^4x, \\x in [0,[pi]/2].$

Intersecting points are x=0 and x =pi/2

Since rotated about x = pi/2 we get

using cylindrical shell method

Volume = $2\pi rh\\=2\pi \int\limits^\frac{\pi}{2} _0 {xy} \, dx \\=2\pi \int\limits^\frac{\pi}{2} _0 (x+\frac{\pi}{2} )(sin^2 x -sin^4 x) dx\\$

From wolfram alpha we find that

Volume= $2\pi (\frac{3\pi^2 }{64)} =\frac{6\pi^3}{64}$

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3 years ago

A quotient of a number 4 at most 5

Kitty [74]

The answer would be x/4<=5

8 0

3 years ago

The price of a technology stock has dropped to $9.61 today. Yesterday's price was $9.72. Find the percentage decrease. Round you

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3 years ago

What is the area of a parallelogram whose vertices are A(−12, 2) , B(6, 2) , C(−2, −3) , and D(−20, −3) ? Enter your answer in t

nikdorinn [45]

Let

$A(-12,2)\\B(6,2)\\C(-2,-3) \\D(-20.-3)\\E(-12.-3)$

using a graphing tool

see the attached figure to better understand the problem

we know that

Parallelogram is a quadrilateral with opposite sides parallel and equal in length

$AB=CD \\AD=BC$

The area of a parallelogram is equal to

$A=B*h$

where

B is the base

h is the height

the base B is equal to the distance AB

the height h is equal to the distance AE

Step 1

Find the distance AB

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-12,2)\\B(6,2)$

substitute the values

$d=\sqrt{(2-2)^{2}+(6+12)^{2}}$

$d=\sqrt{(0)^{2}+(18)^{2}}$

$dAB=18\ units$

Step 2

Find the distance AE

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-12,2)\\E(-12.-3)$

substitute the values

$d=\sqrt{(-3-2)^{2}+(-12+12)^{2}}$

$d=\sqrt{(-5)^{2}+(0)^{2}}$

$dAE=5\ units$

Step 3

Find the area of the parallelogram

The area of a parallelogram is equal to

$A=B*h$

$A=AB*AE$

substitute the values

$A=18*5=90\ units^{2}$

therefore

the answer is

the area of the parallelogram is $90\ units^{2}$

5 0

3 years ago

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Sketch the graph of the given function. Then state the function's domain and range. y = 4(2+)-3

creativ13 [48]

Answer:

D(f) = R

Range = R

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4 years ago