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3 years ago

.12 people go to a meeting. How many hands will they shake if they all shake each other's hands

1 answer:

5 0

Well if each person shakes someone else’s hand 12 times and there’s 12 people, the 12 people x 12 hands = 144 hands shook

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A)180.48 m2 B)180.48 m C)80.48 m2 D)80.48 m

MissTica

Answer:

80.48m2

Step-by-step explanation:

I think this is right but it may be wrong.

4 0

2 years ago

What are the x-intercepts of the quadratic function?

maw [93]

To find the x intercept set y = 0

x^2 + x - 2 =0

(x+2)(x-1) = 0

x = -2 , x = 1

8 0

3 years ago

Read 2 more answers

Melissa has $100 in the bank. She plans to deposit $40 per week until she reaches $500. What is the rate of change? Explain what

Wewaii [24]

Answer:

$40 per week

Step-by-step explanation:

Step one:

Given data

the initial amount is = $100

the total amount= $500

let the number of weeks be x

Step two:

The expression for the scenario is

$500= 100+40x-------1$

From the expression above, the rate of the change is $40 per week.

this means that in every week the account will be increased by $40

5 0

2 years ago

Place on,number line

Alex

A goes between -1 and -1/2

8 0

3 years ago

Read 2 more answers

Find the roots of the equation x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits

scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

$x^{2} + 3x - 8^{- 14} = 0$

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

The above solution is for the quadratic equation of the form:

$ax^{2} + bx + c = 0$

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

From the given eqn

a = 1

b = 3

c = $- 8^{- 14}$

Now, using the above values in the formula mentioned above:

$x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)$

Now, Rationalizing the above eqn:

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

$x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

Solving the above eqn:

$x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}$

Solving with the help of caculator:

$x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}$

The precise value upto three decimal places comes out to be:

$x_{1, 1'} = 0.758\times 10^{- 14}$

5 0

3 years ago