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3 years ago

320,040 in expanded form and with names

Mathematics

2 answers:

Mandarinka [93]3 years ago

7 0

Three hundred and twenty thousand and forty

kozerog [31]3 years ago

4 0

300,000+20,000+40

Three twenty thousand, forty

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Henry drew the model below of his yard. He said the perimeter of the yard is 48 feet. He knows that one side is 9 feet wide. How

saw5 [17]

Answer:

15 feets

Step-by-step explanation:

Perimeter of a rectangle = 2(l + w)

l = Length ; w = width

Perimeter, p = 48

Length of all sides

p = 2(l + w)

48 = 2(l + 9)

48 = 2l + 18

48 - 18 = 2l

30 = 2l

l = 30/2

l = 15

Length of the sides = 15 feets

8 0

2 years ago

Figure A and Figure B are similar with a ratio of similarity of 1/8, and the area of figure A is 13 units, what is the area of f

nikdorinn [45]

Answer:

0.2

Step-by-step explanation:

Similar triangles are triangles which have the same shape but not the same size. This means their angle measures are equal but their side lengths are not instead they are proportional. This means that if a rectangle has sides 3 by 4 its area will be 12. But its image after being dilated by 2 is 6 by 8 or twice the side. Will the area also be twice the size? The area of the image is 6*8 = 48. This is 4 times bigger than 12. Not twice as big. So the similarity of the area is the scale factor squared.

So if figure A has area 13 units. And they have a ratio or scale factor of 1/8 then the area sclae factor will be 1/8*1/8 = 1/64.

So 13*1/64 will be the area of figure B.

13* 1/64 = 13/64 = 0.2

6 0

3 years ago

Graph the hyperbola using the transverse axis, vertices, and co-vertices:

Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

y = ±6/3x

Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

(0 - 3, 0) and (0 + 3, 0)

Evaluate

(-3,0) and (3, 0)

See attachment for the graph of the hyperbola