Sub x = 2-y^2 to Q, we get:
Q = 3(2-y^2)*y^2
let y^2 = k
Q = 3(2-k)k = 3(2k-k^2)
2k-k^2 has a max when k = 1
Then y^2 = 1 -> y = 1 or -1
Answer:
4
Step-by-step explanation:
Answer:
y = 1/2
Step-by-step explanation:
Y+3/5 = 1 1/10
Subtract 3/5 from both sides.
y = 1/2
Answer:
<h2>400</h2>
Step-by-step explanation:
