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3 years ago

!!!!please helppppppp

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

8 0

9514 1404 393

Answer:

13/18

Step-by-step explanation:

5 of the 18 students have a cat, so 13 of them do not.

The probability that a student in the group does not have a cat is 13/18.

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The median of a set of consecutive odd integers is 138. If the greatest integer in the set is 145, what is the least integer in

garri49 [273]

Answer:

131

Step-by-step explanation:

Given that:

Median of a consecutive odd integers = 138

Greatest integer In dataset = 145

Least integer in dataset =

Since the integers are consecutive ;

Number of integers to greatest integer value : Greatest integer - median value = 145 - 138 = 7

Hence, 7 integers before the median value should give us the least integer value ;

138 - 7 = 131

CHECK:

131,132,133,134,135,136,137,138,139,140,141,142,143,144,145

Median = (n+1)/2 th term

Median = (15+1)/2 = 8th term = 138

Highest = 145

Least = 131

7 0

3 years ago

What expression is equivalent to ^3 square root of 2y^3 times 7 square root of 18y

Mumz [18]

Answer:

$\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

Step-by-step explanation:

The question is poorly formatted.

Given

$\sqrt[3]{2y^3} * 7\sqrt{18y}$

Required

Derive an equivalent expression

$\sqrt[3]{2y^3} * 7\sqrt{18y}$

Express 18 as 9 * 2

$\sqrt[3]{2y^3} * 7\sqrt{9 * 2y}$

Split the expression as follows:

$\sqrt[3]{2y^3} * 7\sqrt{9} * \sqrt{2y}$

Take positive square root of 9

$\sqrt[3]{2y^3} * 7*3 * \sqrt{2y}$

$\sqrt[3]{2y^3} * 21 * \sqrt{2y}$

$21*\sqrt[3]{2y^3} * \sqrt{2y}$

The cube root can be rewritten to give:

$21*\sqrt[3]{2}*\sqrt[3]{y^3} * \sqrt{2y}$

$\sqrt[3]{y^3} = y^{3*\frac{1}{3}} = y$

So, we have:

$21*\sqrt[3]{2} * y * \sqrt{2y}$

Rewrite as:

$21y *\sqrt[3]{2} * \sqrt{2y}$

Split $\sqrt{2y$

$21y *\sqrt[3]{2} * \sqrt{2} * \sqrt{y}$

Collect Like Terms

$21y*\sqrt{y} *\sqrt[3]{2} * \sqrt{2}$

Represent in index form

$21y*y^{\frac{1}{2}} *2^\frac{1}{3} *2^\frac{1}{2}$

Apply law of indices

$21*y^{1+\frac{1}{2}} *2^{\frac{1}{3} +\frac{1}{2} }$

$21*y^{\frac{2+1}{2}} *2^{\frac{2+3}{6}}$

$21*y^{\frac{3}{2}} *2^{\frac{5}{6}}$

$21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

Hence:

$\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

6 0

3 years ago

8÷2(2+2). I need help finding the correct answer. 8÷2(2+2). I need help finding out if it is 1 or 16.

deff fn [24]

Answer:

The answer is 16

Step-by-step explanation:

8 divided by 2 (2+2)=16

8 0

4 years ago

Read 2 more answers

Find the explicit formula for the arithmetic sequence -31,-27,-23,-19 b(n)= ?

BigorU [14]

b(n)=-31+4(n-1) is the explicit formula

4 0

4 years ago

Read 2 more answers

A dieter believes that the average number of calories in a homemade peanut better cookie is more than the average number of calo

zalisa [80]

The confidence interval formula is computed by:

Xbar ± Z s/ sqrt (n)

Where:

Xbar is the mean

Z is the z value

S is the standard deviation

N is the number of samples

So our given are:

90% confidence interval with a z value of 1.645

Sample size 40, 45

Mean 180, 179

Standard deviation 2, 4

So plugging that information in the data will give us a confidence interval:

For 1:

Xbar ± Z s/ sqrt (n)

= 180 ± 1.645 (2 / sqrt (40))

= 180 ± 1.645 (0.316227766)

= 180 ± 0.520194675

= 179.48, 180.52

For 2:

Xbar ± Z s/ sqrt (n)

= 179 ± 1.645 (4 / sqrt (45))

therefore, the answer is letter b

8 0

4 years ago