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lana [24]
3 years ago
14

Solve. You must factor first. 5x^2+ 17x+ 14=0 Please show work

Mathematics
1 answer:
Soloha48 [4]3 years ago
4 0

Answer:

the answer is <em><u>X</u></em><em><u>=</u></em><em><u>-</u></em><em><u>3</u></em>

<em><u>1</u></em><em><u>)</u></em><em><u> </u></em><u>5</u><em><u>x</u></em><u>^</u><u>2</u><u>+</u><u>1</u><u>7</u><em><u>x</u></em><u>+</u><u>1</u><u>4</u><u>=</u><u>0</u>

<u>2</u><u>)</u><u>5</u><em><u>x</u></em><u>^</u><u>2</u><u>+</u><u>1</u><u>7</u><em><u>x</u></em><em><u>=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em><em><u>+</u></em><em><u>0</u></em>

<em><u>3</u></em><em><u>)</u></em><em><u>2</u></em><em><u>5</u></em><em><u>x</u></em><em><u>+</u></em><em><u>1</u></em><em><u>7</u></em><em><u>x</u></em><em><u>=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em>

<em><u>4</u></em><em><u>)</u></em><em><u>4</u></em><em><u>2</u></em><em><u>x</u></em><em><u>=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em>

<em><u>5</u></em><em><u>)</u></em><em><u>4</u></em><em><u>2</u></em><em><u>x</u></em><em><u>/</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em>

<em><u>6</u></em><em><u>)</u></em><em><u>x</u></em><em><u>=</u></em><em><u>-</u></em><em><u>3</u></em>

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Consider Z1= 4-4 radical 3i and Z2= -16 i. What is Z1-Z2?
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Answer:

Option (3)

Step-by-step explanation:

Z_1=4-4\sqrt{3}i

Z_2=-16i

Z_1-Z_2=(4-4\sqrt{3}i)-(-16i)

            =4-4\sqrt{3}i+16i

            =4-(4\sqrt{3}i-16i)

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A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the
amm1812

Answer:

s(t)=(ln|7|+ln|2|)\,ft

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\

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v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\

Using initial value

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\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft

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Answer:

The correct option is C) The results were not statistically significant but were practically significant.

Step-by-step explanation:

Consider the provided information.

They found that the difference in these shelf lives had a p-value of 0.24. Assume an α of 0.05.

We reject the null hypothesis if p value is less than α.

We are fail to reject null hypothesis if p value is greater or equal to α.

Here p value is greater than 0.05.

So, we do not reject null hypothesis and conclude that result is not statistically significant. But, there is a practical difference between 3 days and 7 days.

Therefore, the correct option is C) The results were not statistically significant but were practically significant.

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