<span>A chord to a circle is any straight line which starts from one point on the circumference to another. For the given circle, the chords of the circle are AD and BE. Therefore, the correct option from the options is option B.Hope I helped! :) Cheers!</span>
Since measure REU equal measure SFT, RE=FT and SF=EU then the two triangles REU et SFT are similar.
Then we deduce that the two sides RU and ST are equal, RU=ST.
Also, since the two triangles above are similar, then the two angles FST and RUE are equal. We deduce that the two lines RU and ST are parallel (interior opposite angles principles.)
We have two facts now:
RU = ST and RU parallel to ST, we deduce that the quadrilateral is a parallelogram.
Answer:
It is choice A.
Step-by-step explanation:
The general form is (x - h)^2 / a^2 + (x - k)^2/b^2 = 1 where (h, k) is the center, 2a = major axis and 2b = minor axis.
The ellipse in the question has a^2 > b^2 so the major axis is parallel to the x axis.
The minor axis which is parallel to the y-axis is of length 10 so b^2 = (1/2 * 10)^2
= 25 so we can eliminate C.
The center of the ellipse = the midpoint of a line joining the focii so it is:
( 3+ 7)/2, 6)
= (5,6).
As (h, k) is the center we have h = 5 and k = 6.
So it is choice A.
Answer:
ΔDCE by ASA
Step-by-step explanation:
The marks on the diagram show AE ≅ DE. We know vertical angles AEB and DEC are congruent, and we know alternate interior angles BAE and CDE are congruent. The congruent angles we have identified are on either end of the congruent segment, so the ASA theorem applies.
Matching corresponding vertices, we can declare ΔABE ≅ ΔDCE.