Answer:
The equation of the line parallel to y=4/3x−4 that passes through (-4,6) is y=4/3x−10/3 .
The equation of the line perpendicular to y=43x−4 that passes through (-4,6) is y=−3/4x+10 .
Step-by-step explanation:
Parallel means equal slopes. Hence, the slope of the line parallel to y=4/3x+3 is 4/3 . We know our slope and we know a point. We can therefore use point-slope form to determine the equation of the new line.
y−y1=m(x−x1)
y−6=4/3(x−4)
y−6=4/3x−16/3
y=4/3x−7/3
The equation of the line parallel to y=4/3x−4 that passes through (-4,6) is y=4/3x−10/3 .
Question #2:
Perpendicular means negative reciprocal slopes. Hence, the slope perpendicular to y=4/3x+3 is y=−3/4 . We know our slope and we know a point. We can therefore use point-slope form to determine the equation of the new line.
y−y1=m(x−x1)
y−6=−3/4(x-4)
y−6=−3/4x+6
y=−3/4x+10
The equation of the line perpendicular to y=43x−4 that passes through (-4,6) is y=−3/4x+10 .
I hope this helps you
x= -3
y=3. (-3)+2
y= -9+2
y = -7
Multiply the area of all sides (10*5)*2+(10*4)*2+(4*5)*2 to get 220 in^2
