Answer:
Step-by-step explanation:
When m+3=-5, collection of like terms says; -5-3
Now,-5+-3 = -8 and -2≠-8 hence,they aren't equivalent
Answer:
![16\sqrt{3}\:\mathrm{units^2}](https://tex.z-dn.net/?f=16%5Csqrt%7B3%7D%5C%3A%5Cmathrm%7Bunits%5E2%7D)
Step-by-step explanation:
The area of an equilateral triangle with side length
is equal to
. Since the perimeter is 24 units and there are three equal sides to an equilateral triangle, each side is
units.
Substituting in this value, we get:
![\frac{\sqrt{3}}{4}8^2=\frac{64\sqrt{3}}{4}=\boxed{16\sqrt{3}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D8%5E2%3D%5Cfrac%7B64%5Csqrt%7B3%7D%7D%7B4%7D%3D%5Cboxed%7B16%5Csqrt%7B3%7D%7D)
Answer:
The range of T is a subspace of W.
Step-by-step explanation:
we have T:V→W
This is a linear transformation from V to W
we are required to prove that the range of T is a subspace of W
0 is a vector in range , u and v are two vectors in range T
T = T(V) = {T(v)║v∈V}
{w∈W≡v∈V such that T(w) = V}
T(0) = T(0ⁿ)
0 is Zero in V
0ⁿ is zero vector in W
T(V) is not an empty subset of W
w₁, w₂ ∈ T(v)
(v₁, v₂ ∈V)
from here we have that
T(v₁) = w₁
T(v₂) = w₂
t(v₁) + t(v₂) = w₁+w₂
v₁,v₂∈V
v₁+v₂∈V
with a scalar ∝
T(∝v) = ∝T(v)
such that
T(∝v) ∈T(v)
so we have that T(v) is a subspace of W. The range of T is a subspace of W.
Answer:
r = 1.9
Step-by-step explanation:
7r + 7 = 20.3
<u> - 7 - 7 </u>
7r = 13.3
divide by 7
r = 1.9
Answer:
1 gallon=3.79 liters 2 liter juice bottle would hold more
Step-by-step explanation: