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noname [10]
2 years ago
15

What is the general equation of a sine function with an amplitude of 2, a period of Pi and a horizontal shift of Pi units? y = 2

sine (2 (x minus pi)) y = 2 sine (4 (x pi)) y = sine (0. 5 (x minus pi)) y = sine (2 (x pi)).
Mathematics
1 answer:
jonny [76]2 years ago
4 0

The general equation of the sine function is \rm y= 2sin(2(x-\pi). The sine and cosine of an acute angle are utilized to find the angle of the triangle.

<h3>What is sin function?</h3>

The sine and cosine of an angle are trigonometric functions. In the context of a right triangle, the sine and cosine of an acute angle are used to find the angle of the triangle.

The standard general equation of a sine function is given as;

\rm y= AsinB(x-C)+D

Where A denotes the amplitude, B is the frequency, D is the vertical shift and  C is the phase shift.

The given data in the problem is;

A is the amplitude= 2

B is the frequency=2

D is the vertical shift =0

C is the phase shift.=\pi

The general equation is found as;

\rm y= 2sin(2(x-\pi)

Hence the general equation of the sine function is \rm y= 2sin(2(x-\pi).

To learn more about the sin function refer to the link;

brainly.com/question/6826226

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