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noname [10]
2 years ago
15

What is the general equation of a sine function with an amplitude of 2, a period of Pi and a horizontal shift of Pi units? y = 2

sine (2 (x minus pi)) y = 2 sine (4 (x pi)) y = sine (0. 5 (x minus pi)) y = sine (2 (x pi)).
Mathematics
1 answer:
jonny [76]2 years ago
4 0

The general equation of the sine function is \rm y= 2sin(2(x-\pi). The sine and cosine of an acute angle are utilized to find the angle of the triangle.

<h3>What is sin function?</h3>

The sine and cosine of an angle are trigonometric functions. In the context of a right triangle, the sine and cosine of an acute angle are used to find the angle of the triangle.

The standard general equation of a sine function is given as;

\rm y= AsinB(x-C)+D

Where A denotes the amplitude, B is the frequency, D is the vertical shift and  C is the phase shift.

The given data in the problem is;

A is the amplitude= 2

B is the frequency=2

D is the vertical shift =0

C is the phase shift.=\pi

The general equation is found as;

\rm y= 2sin(2(x-\pi)

Hence the general equation of the sine function is \rm y= 2sin(2(x-\pi).

To learn more about the sin function refer to the link;

brainly.com/question/6826226

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vampirchik [111]
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compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.
Nina [5.8K]

\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of$\vec{b}$onto $\vec{a}$means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0
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Therefore the sale  tax percentage                   = ⁹²/₉₂₀  x 100

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