Heads or tails lands 1 time in 1 coin flip
Answer:
Step-by-step explanation:
Given that,
Outcomes Heads= 4heads and
Outcomes Tails= 6tails
Total outcome of events n=10
Probability of head in is first throw is, the is the outcome of head divide by the total possible outcomes
P(Head in first throw)=4/10
P(H)=2/5
P(H) = 0.4
P(H) =40%
Answer:
q= -ck+dp/
-k+d
Step-by-step explanation:
Step 1:
Multiply both sides by p.
dp=ck−kq+pq
Step 2:
Flip the equation.
ck−kq+pq=dp
Step 3:
Add -ck to both sides.
−kq+pq=−ck+dp
Step 4:
Factor out variable q.
q(−k+p)=−ck+dp
Step 5:
Divide both sides by -k+p.
q= -ck+dp/
-k+d
Sorry if it's all letters and u needed numbers.
Answer:
x=3.4
Step-by-step explanation:
I could be wrong but I'm pretty sure this is the answer.
Refer to the image attached.
Since, we have to divide the polynomial 
by (x+2) using synthetic division.
We will divide the coefficients 4 -2 3 by -2
First term = 4 will remain same.
Second term = 
So, second term = -10
Third term = 
So, third term = 23
So, 4 -10 23 is the correct answer
So, Option 2 is the correct answer.
