x=31,y=−61
Put the equations in standard form and then use matrices to solve the system of equations.
5x+4y=1,3x−6y=2
Write the equations in matrix form.
(534−6)(xy)=(12)
Left multiply the equation by the inverse matrix of (534−6).
inverse((534−6))(534−6)(xy)=inverse((534−6))(12)
The product of a matrix and its inverse is the identity matrix.
(1001)(xy)=inverse((534−6))(12)
Multiply the matrices on the left hand side of the equal sign.
(xy)=inverse((534−6))(12)
For the 2×2 matrix (acbd), the inverse matrix is (ad−bcdad−bc−cad−bc−bad−bca), so the matrix equation can be rewritten as a matrix multiplication problem.
(xy)=(5(−6)−4×3−6−5(−6)−4×33−5(−6)−4×345(−6)−4×35)(12)
Do the arithmetic.
(xy)=(71141212−425)(12)
Multiply the matrices.
(xy)=(71+212×2141−425×2)
Do the arithmetic.
(xy)=(31−61)
Extract the matrix elements x and y.
x=31,y=−61
Answer:
C
Step-by-step explanation:
okay, this is actually pretty easy because it just works with simple translations.
(x+a)^2 + b
if a is positive, the graph shifts left
if a is negative, the graph shifts right
if b is positive, the graph shifts up
if b is negative, the graph shifts down
so since the quadratic, is starts at the origin and is shift 3 to the left, and 2 up:
the equation is
(x+3)^2 + 2
Answer:
If I dont get 5 stars u guys hate kobe bryant
Step-by-step explanation:
d
You just have to reflect it over the blue line, so if one point is 2 squares from the blue line then you will make it 2 squares away on the other side of the blue line. The y point will stay the same so they will be the same height
Answer:
x≥5
Step-by-step explanation:
3(x+15)≤5(x+2)+15
3x+45≤5x+10+15
3x+35≤5x+25
3x-5x≤25-35
-2x≤-10
x≥5
{x:xEx:6,7,8,9,10....}
Hope this helps ;) ❤❤❤
