Volume of pyramid:

A - base area
H - height
First count volume of one pyramid:
![V=\dfrac{1}{3} \cdot 3 \cdot 4=4 [\hbox{inch}^3]](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7D%20%5Ccdot%203%20%5Ccdot%204%3D4%20%5B%5Chbox%7Binch%7D%5E3%5D)
So by using 576 inch^3 you can make 576 : 4 =
144 pyramids
Answer:
1. a
2. d
3. c
4. d?
5. cant answer cause I cannot see the data
N'(-2,2)
G'(-2,-4)
H'(6,-4)
Answer:
6 square units
Step-by-step explanation:
Given shape is of a trapezoid:

Area of shape = area of square + area of triangle
