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mrs_skeptik [129]
3 years ago
9

Subtract: 3/4y-(1/2y+1/3)

Mathematics
1 answer:
12345 [234]3 years ago
5 0

Answer: y=72

Step-by-step explanation:

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The surface areas of two similar rectangular prisms are 361 m2 and 441 m2. What is the scale factor of the larger prism to the s
Elis [28]

Option C:

The scale factor of the larger prism to the smaller prism is \frac{21}{19}.

Solution:

Two rectangular prisms are similar.

Surface area of the smaller prism = 361 cm²

Surface area of the larger prism = 441 cm²

Scale factor of larger prism to smaller prism

                           $=\frac{\sqrt \text{{Surface area of larger prism}} }{\sqrt\text{{Surface area of smaller prism}  }}

                           $=\frac{\sqrt {441} }{\sqrt{361}}

                           $=\frac{\sqrt {21^2} }{\sqrt{19^2}}

Both square and square roots are cancelled, we get

                            $=\frac{21}{19}

The scale factor of the larger prism to the smaller prism is \frac{21}{19}.

Hence Option C is the correct answer.

6 0
4 years ago
What is the solution to the rational equation x over 2x minus 1 plus 1 over 4 equals 2 over 2x minus 1
weeeeeb [17]

Answer:

the solution of given rational equation is x= 3/2

Step-by-step explanation:

\frac{x}{2x-1}+\frac{1}{4} = \frac{2}{2x-1}

We need to solve the above rational equation and find value of x

Finding LCM of 4 and (2x-1) we get 4(2x-1).

Multiplying 4(2x-1) on both sides of equation and solving

\frac{x}{2x-1}*4(2x-1)+\frac{1}{4}*4(2x-1) = \frac{2}{2x-1}*4(2x-1)\\4x+2x-1=8\\6x-1=8\\6x=8+1\\6x=9\\x=9/6\\x=3/2

So, the solution of given rational equation is x= 3/2

6 0
4 years ago
From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm find the radius of
Umnica [9.8K]

\large\bold{{Question :}}

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm find the radius of the circle.

\large\bold\red{\underline{Solution :-}}

Here, O is the center of the circle.

<u>⟼</u><u> </u><u>Given</u><u> </u><u>:</u>

  • OQ = 25 cm
  • PQ = 24 cm

<u>⟼</u><u> </u><u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u> </u> We have to find the radius OP.

Since QP is tangent, OP perpendicular to QP.

(Since, Tangent is Perpendicular to Radius ⠀⠀⠀⠀⠀⠀⠀at the point of contact)

So, ∠OPQ=90°

<u>⟼</u><u> </u><u>By</u><u> </u><u>Applying</u><u> </u><u>Pythagoras</u><u> </u><u>Theorem</u><u> </u><u>:</u>

OP² + RQ² = OQ²

OP² + (24)² = (25)²

OP² = 625 - 576

OP² = 49

OP = √49

<u>OP</u><u> </u><u>=</u><u> </u><u>7</u><u> </u><u>cm</u>

<u>Hence</u><u>,</u><u> </u><u>The</u><u> </u><u>Radius</u><u> </u><u>is</u><u> </u><u>7</u><u> </u><u>cm</u>

⠀⠀

⠀

<h3>-MissAbhi</h3>

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What is the area, in square feet, of the shaded region? Remember A(Circle) = πr²
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