All categories

3 years ago

Configurative Area Problems Find the area of the shaded region. BRAINLIEST

Mathematics

2 answers:

natali 33 [55]3 years ago

8 0

Answer:

78.54 cm

formula: A= <u>pi x r^2</u>

<u />

babunello [35]3 years ago

7 0

Area of 1/4 = 1/4 x 3.14 x 10 x 10 = 78.5cm2
area of 2 semi circles = 3.14x5x5= 78.5 cm2
78.5+78.5=157cm2

formula: π x r x r = area of circle
1/4 x π x r x r = area of 1/4 of a circle
x = times

You might be interested in

The area of a rectangle is x2 - 2x - 15 and the length of the rectangle is x + 3. Find the width of the rectangle.

Alexandra [31]

The area of the triangle could be determined by multiplying the length and the width. Since, we are given the area and the length, to find the width, you divide the area by the length:

w = A ÷ l
w = (x2 - 2x - 15) ÷ (x+3)

What do you have to multiply to (x+3) to yield x2 - 2x - 15? That would be x - 5. Since the sum of -5 and 3 = -2 (middle term) and the their product is -15 (last term).

Hence, the width is (x-5).

8 0

3 years ago

2/3x=10 thankyou for helping me

Novay_Z [31]

(2/3)x = 10
(3/2)(2/3)x = 10(3/2)
x = 30/2 = 15

6 0

3 years ago

Read 2 more answers

Describe the steps to dividing imaginary numbers and complex numbers with two terms in the denominator?

zlopas [31]

Answer:

Let be a rational complex number of the form $z = \frac{a + i\,b}{c + i\,d}$ , we proceed to show the procedure of resolution by algebraic means:

1) $\frac{a + i\,b}{c + i\,d}$ Given.

2) $\frac{a + i\,b}{c + i\,d} \cdot 1$ Modulative property.

3) $\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)$ Existence of additive inverse/Definition of division.

4) $\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}$ $\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}$

5) $\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}$ Distributive and commutative properties.

6) $\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}$ Distributive property.

7) $\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}$ Definition of power/Associative and commutative properties/ $x\cdot (-y) = -x\cdot y$ /Definition of subtraction.

8) $\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}$ Definition of imaginary number/ $x\cdot (-y) = -x\cdot y$ /Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

Step-by-step explanation:

Let be a rational complex number of the form $z = \frac{a + i\,b}{c + i\,d}$ , we proceed to show the procedure of resolution by algebraic means:

1) $\frac{a + i\,b}{c + i\,d}$ Given.

2) $\frac{a + i\,b}{c + i\,d} \cdot 1$ Modulative property.

3) $\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)$ Existence of additive inverse/Definition of division.

4) $\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}$ $\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}$

5) $\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}$ Distributive and commutative properties.

6) $\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}$ Distributive property.