The answers are x=4 and y=323/2
1) 40/2x-3=8
Multiply both sides by 2x-3 to get rid of fraction
40= 8(2x-3)
Distribute 8
40= 16x-24
Add 24 to both sides
64=16x
Divide by 16
4=x
2) 2y-3/40=8
Multiply both sides by 40 to red rod of fraction
2y-3=320
Add 3 to both sides
2y= 323
Divide by 2
Y=323/2
Now just describe the differences in solving them
FYI / means fraction, right after the slash is bottom of fraction
Answer:
the answer would be 32 then. you start with 7 then add 1 then Multiple by 4 which equals 32
The number of kilometres travelled by the satellite in discuss in which case, the satellite makes 8 revolutions around the earth is; C = 177,271.8 km.
<h3>What is the distance in kilometres covered by the satellite after 8 revolutions?</h3>
Given from the task content, the earth's diameter is; 6371 km and since, the height at which the satellite orbits the earth is; 343km, it follows that the diameter of orbit if the satellite in discuss is;
D = 6371 + (343)×2
Hence, we have; diameter, D = 7057 km.
Hence, the distance travelled after 8 revolutions is;
C = 8 × πd
C = 8 × 3.14 × 7057
C = 177,271.8 km.
Read more on circumference of a circle;
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The area would be .4 cubic feet. The perimeter would be 2.1
