Answer:
Mailing preparation takes 38.29 min max time to prepare the mails.
Step-by-step explanation:
Given:
Mean:35 min
standard deviation:2 min
and 95% confidence interval.
To Find:
In normal distribution mailing preparation time taken less than.
i.eP(t<x)=?
Solution:
Here t -time and x -required time
mean time 35 min
5 % will not have true mean value . with 95 % confidence.
Question is asked as ,preparation takes less than time means what is max time that preparation will take to prepare mails.
No mail take more time than that time .
by Z-score or by confidence interval is
Z=(X-mean)/standard deviation.
Z=1.96 at 95 % confidence interval.
1.96=(X-35)/2
3.92=(x-35)
X=38.29 min
or
Confidence interval =35±Z*standard deviation
=35±1.96*2
=35±3.92
=38.29 or 31.71 min
But we require the max time i.e 38.29 min
And by observation we can also conclude the max time from options as 38.29 min.
Answer:
i think the answer is 5.4
Step-by-step explanation:
:)
4600 pounds
Work: 2.3 * 2000
34 square feet
Explanation:
Cut the shape into two shapes. The bottom will be a square and the top will be a long rectangle.
The area of the rectangle is 18 square feet
(Multiply 9 x 2)
The area of the square is 16 square feet
(Multiply 4 x4)
18 + 16 = 34
MARK BRAINLIESTT
Please! And thank u, trust me, this is the answer
I can’t answer if you don’t show the multiple choice...
