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vlabodo [156]
3 years ago
5

A triangle has a base of 18.1 kilometres and a height of 17.4 kilometres. What is the area?

Mathematics
1 answer:
vampirchik [111]3 years ago
7 0

Answer:

157.47km²

Step-by-step explanation:

Given the following

base of 18.1 kilometres

height of 17.4 kilometres

Area of the triangle = 1/2 * base * height

Area of the triangle = 1/2 * 18.1 * 17.4

Area of the triangle = 314.94/2

Area of the triangle = 157.47km²

Hence the area of the triangle is 157.47km²

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How do you solve 32 - 6x = 53?
katrin2010 [14]

\large\boxed{x=-\frac{7}{2}}

To solve for x, we need to isolate it on one side of the equation.

The most important part of this is knowing that whatever we do to one side of the equation, we must also do to the other.

Subtract 32 from both sides of the equation.

\begin{aligned}32-32-6x&=53-32\\-6x&=21\end{aligned}

Divide both sides of the equation by -6.

\begin{aligned}\frac{-6x}{-6}&=\frac{21}{-6}\\x&=\boxed{-\frac{7}{2}}\end{aligned}

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2 years ago
Read 2 more answers
If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.
Brut [27]

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

(10x - 11) = (8x - 20) + 43

Solve for x

10x - 11 = 8x - 20 + 43

10x - 11 = 8x + 23

Subtract 8x from both sides

10x - 11 - 8x = 8x + 23 - 8x

2x - 11 = 23

Add 11 to both sides

2x - 11 + 11 = 23 + 11

2x = 34

Divide both sides by 2

\frac{2x}{2} = \frac{34}{2}

x = 17

2. m<MKL = 8x - 20

Plug in the value of x

m<MKL = 8(17) - 20 = 136 - 20 = 116°

3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

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3 years ago
29. 83 – 2 · 4 = <br> 30. 3 · 6 – 4 · 2 = <br> 31. 3( 6 – 4) · 2 =
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1) 21.83

2)173.8

3)12

Hope this helps :)

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Creo que te falta información posiblemente la imagen de la finca
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A students cost for last summer at her community college was 2800. She spent 560 of that in books. What percent of last semester
svetoff [14.1K]

Form the ratio 560/2800 and then mult. the result by 100%:

560

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2800

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