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IRISSAK [1]
3 years ago
10

What is the volume of a square prism that is 4 centimeters by 4 centimeters by 8 centimeters

Mathematics
1 answer:
My name is Ann [436]3 years ago
6 0

Answer:

138 is the answer

Step-by-step explanation:

128 square

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Boadu and ansah formed a company and agreed that their annual profit will be shared in the ratio of 4:5 respectively. If at the
lozanna [386]

Answer:

ghs 20,000

Step-by-step explanation:

If Boadu and ansah formed a company and agreed that their annual profit will be shared in the ratio of 4:5 respectively, the total ratio will be 4 + 5 = 9

Let Boadu share be x

Let ansah share be y

If at the end of the year ansah received ghs5,000 more than Boadu, then;

y = 5000 + x

Boadu share = 4/9 * (x+y)

x+y is the total amount shared

x = 4/9 * (x+y)

Substitute y = 5000 + x

9x = 4(x+y)

9x = 4x + 4y

9x - 4x = 4y

5x = 4y

5x = 4(5000+x)

5x = 20,000 + 4x

5x-4x = 20,000

x = 20,000

Hence Boadu share is ghs 20,000

3 0
3 years ago
A movie, including the previews, is 2 hours and 40
ra1l [238]

Answer:

7/8

Step-by-step explanation:

3 0
3 years ago
Can you please help me answer this question what's a+3
Inessa [10]

Answer:

a+3

Step-by-step explanation:

You cannot go any further in answering this question.  These two terms are not like terms so they cannot be combined.  Therefore, the answer is just a+3 itself.

7 0
3 years ago
Whats equivalent to 4/16
Rashid [163]
1/4, 0.25, and 25%.

Hope this answer helps! feel free to ask any additional questions :)
6 0
3 years ago
Read 2 more answers
Evaluate the integral. 3 2 t3i t t − 2 j t sin(πt)k dt
sveta [45]

∫(t = 2 to 3) t^3 dt

= (1/4)t^4 {for t = 2 to 3}

= 65/4.

----

∫(t = 2 to 3) t √(t - 2) dt

= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2

= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du

= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}

= 26/15.

----

For the k-entry, use integration by parts with

u = t, dv = sin(πt) dt

du = 1 dt, v = (-1/π) cos(πt).


So, ∫(t = 2 to 3) t sin(πt) dt

= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt

= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]

= 5/π + 0

= 5/π.

Therefore,

∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.

3 0
3 years ago
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