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enyata [817]
3 years ago
7

Which equation represents this sentence? 10 points! Twenty-eight is the product of four and a number. 28=4n 28=4+n 28=4n 28=4n

Mathematics
1 answer:
Gemiola [76]3 years ago
3 0

Answer:

28=4n

Step-by-step explanation:

since it is said that 28 is the product of 4 and a number

therefore, 28 is the final answer and we use n to represent the unknown number, and it is also said product of 4 and the unknown number thereby giving us our final answer 28=4n

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Multiply: x^2×y^2 × mn / x^11
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Answer:

Answer: |

1/(a b x y)

Step-by-step explanation:

Simplify the following:

(x^2 y^2 m n x^8 y^9 m n)/(x^11 y^12 m^2 n^2 a b)

Combine powers. (m n x^8 y^9 m n x^2 y^2)/(a b m^2 n^2 x^11 y^12) = (m^(1 + 1 - 2) n^(1 + 1 - 2) x^(8 + 2 - 11) y^(9 + 2 - 12))/(a b):

(m^(1 + 1 - 2) n^(1 + 1 - 2) x^(8 + 2 - 11) y^(9 + 2 - 12))/(a b)

1 + 1 - 2 = 0:

(m^0 n^(1 + 1 - 2) x^(8 + 2 - 11) y^(9 + 2 - 12))/(a b)

1 + 1 - 2 = 0:

(m^0 n^0 x^(8 + 2 - 11) y^(9 + 2 - 12))/(a b)

8 + 2 - 11 = -1:

(m^0 n^0 x^(-1) y^(9 + 2 - 12))/(a b)

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(m^0 n^0 y^(-1))/(x a b)

n^0 = 1:

m^0/(a b x y)

m^0 = 1:

6 0
2 years ago
Read 2 more answers
What is the volume of a prism with a height of 4 feet and a base area of 9 square feet?
Simora [160]

Answer:

36 units³

Step-by-step explanation:

To find the volume of a prism, you must multiply the base times the height. 4×9=36.

3 0
4 years ago
The diagram shows how cos θ, sin θ, and tan θ relate to the unit circle. Copy the diagram and show how sec θ, csc θ, and cot θ r
DIA [1.3K]
<span>Copy the diagram and show how sec θ, csc θ, and cot θ relate to the unit circle. 

The representation of the diagram is shown if Figure 1. There's a relationship between </span>sec θ, csc θ, and cot θ related the unit circle. Lines green, blue and pink show the relationship. 

a.1 First, find in the diagram a segment whose length is sec θ. 

The segment whose length is sec θ is shown in Figure 2, this length is the segment \overline{OF}, that is, the line in green.

a.2 <span>Explain why its length is sec θ.

We know these relationships:

(1) sin \theta=\frac{\overline{BD}}{\overline{OB}}=\frac{\overline{BD}}{r}=\frac{\overline{BD}}{1}=\overline{BD}

(2) </span>cos \theta=\frac{\overline{OD}}{\overline{OB}}=\frac{\overline{OD}}{r}=\frac{\overline{OD}}{1}=\overline{OD}
<span>
(3) </span>tan \theta=\frac{\overline{FD}}{\overline{OC}}=\frac{\overline{FC}}{r}=\frac{\overline{FC}}{1}=\overline{FC}
<span>
Triangles </span>ΔOFC and ΔOBD are similar, so it is true that:

\frac{\overline{FC}}{\overline{OF}}= \frac{\overline{BD}}{\overline{OB}}<span>

</span>∴ \overline{OF}= \frac{\overline{FC}}{\overline{BD}}= \frac{tan \theta}{sin \theta}= \frac{1}{cos \theta} \rightarrow \boxed{sec \theta= \frac{1}{cos \theta}}<span>

b.1 </span>Next, find cot θ

The segment whose length is cot θ is shown in Figure 3, this length is the segment \overline{AR}, that is, the line in pink.

b.2 <span>Use the representation of tangent as a clue for what to show for cotangent. 
</span>
It's true that:

\frac{\overline{OS}}{\overline{OC}}= \frac{\overline{SR}}{\overline{FC}}

But:

\overline{SR}=\overline{OA}
\overline{OS}=\overline{AR}

Then:

\overline{AR}= \frac{1}{\overline{FC}}= \frac{1}{tan\theta} \rightarrow \boxed{cot \theta= \frac{1}{tan \theta}}

b.3  Justify your claim for cot θ.

As shown in Figure 3, θ is an internal angle and ∠A = 90°, therefore ΔOAR is a right angle, so it is true that:

cot \theta= \frac{\overline{AR}}{\overline{OA}}=\frac{\overline{AR}}{r}=\frac{\overline{AR}}{1} \rightarrow \boxed{cot \theta=\overline{AR}}

c. find csc θ in your diagram.

The segment whose length is csc θ is shown in Figure 4, this length is the segment \overline{OR}, that is, the line in green.

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Answer:

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because -10 x 5 = -50 and -10 + 5 = -5!

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