We know that According to Algebra of Real Functions :
If f and g are two real functions which are defined under the same domain then 

Now we need find the Domain of this Function :
The Condition for Square Root to be defined is any Expression under it should be Greater than or Equal to Zero.
When Function is a Fraction, it Cannot be defined when the denominator becomes zero. Because when the denominator is zero, the fraction tends to ∞ (because anything divided by zero tends to ∞)
According to Above Conditions Described above, The Given Function is Definable only when the Expression which is under the Square Root is Greater than Zero and x ≠ 0
⇒ 3x - 9 > 0
⇒ 3x > 9
⇒ x > 3
⇒ The Domain of the Given Function is (3 , ∞)
1st Option is the Answer
Answer:
C. 7 weeks.
Step-by-step explanation:
Since the shrub was 64 cm tall at first, take away 64 from 76.6. Now we are left with 12.6. Let's divide 12.6 by 1.8 (that's how many cm it grows per week). When we do this, we are left with 7. This means it took 7 weeks for the shrub to reach 76.6 cm. I hope this helps!
(1,0),(6,-3)
slope(m) = (-3 - 0) / (6 - 1) = -3/5
y - y1 = m(x - x1)
slope(m) = -3/5
(6,-3)....x1 = 6 and y1 = -3
now sub....and pay attention to ur signs
y - (-3) = -3/5(x - 6)......this is not the final answer....but it seems to be what ur question is asking for.
Answer:
The answer is to this is D. 210
-q/-7≥-1
q/7≥-1
q≥-1*7
q≥-7
Solution: q≥-7 or q∈[-7,+∞).