Use this version of the Law of Cosines to find side b:
b^2 = a^2 + c^2 − 2ac cos(B)
We want side b.
b^2 = (41)^2 + (20)^2 - 2(41)(20)cos(36°)
After finding b, you can use the Law of Sines to find angles A and C or use other forms of the Law of Cosines to find angles A and C.
Try it....
The answer is 19.. substitute -1 into the function whenever you see x put -1 there. This implies that 3+16 =19
Answer:
I(7) = 22.96 W/m²
Step-by-step explanation:
Let intensity of light, be I(d) where d is distance. There must be a proportionality factor K such as
I(d) = K /d²
Now for d = 5 m I(d) = K* 1/d²
then 45 * 25 = K
K = 1125
To find the intensity when the distance from the light bulb is 7 m away
I(7) = K / 49
I(7) = 1125/49 W/m²
I(7) = 22.96 W/m²
What are you asking here exactly
Answer: 32.23°
Suppose the setpoint of a helicopter is A and that of a car is C and that of the road is B
The distance from the helicopter to the car and the road forms a right triangle
=> ΔABC is a right triangle at B
=> the angle of depression from the helicopter from the car is ∠ACB
we have: ΔABC is a right triangle => sin ∠ACB = 24/45
=> m∠ACB = 32.23°
Step-by-step explanation:
