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3 years ago

The expression x^4-16 is equivalent to the product of (x+2) and p(x) which expression could represent p(x)

1 answer:

3 0

Easy
differnce of 2 perfect squares
a²-b²=(a+b)(a-b)

in this case
x⁴=(x²)²
16=4²

(x²)²-4²=(x²+4)(x²-4)
x²-4 can be factored since 4=2²
x²-2²=(x+2)(x-2)

complete factored form is
(x²+4)(x+2)(x-2)
gegroup to seperate (x+2)
(x+2)[(x²+4)(x-2)]
(x+2)p(x)

p(x)=(x²+4)(x-2)
expanded
p(x)=x³-2x²+4x-8

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2 years ago

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2 years ago

For the functions f and g, find (f o g)(8). f(x) = 17x^2 - 10x, g(x) = 9x - 9

Andreyy89

Hey mate. Here is your answer.

Set up the composite function and evaluate.

g (17x^2 - 10x) = 153x^2 - 90x - 9

Hope this helps.

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3 years ago

The water diet requires you to drink two cups of water every half hour from the time you get up until you go to bed, but otherwi

Elan Coil [88]

Answer:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150

Weight after diet 170 130 215 152

We define the random variable $D = before-after$ and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

And the deviation with:

$s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}$

And after replace we got:

$\bar D= 7, s_d = 13.638$

And the confidence interval for this case would be given by:

$\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}$

The degrees of freedom are given by:

$df = n-1= 4-1=3$

For the 95% of confidence the value for the significance is $\alpha=0.05$ and the critical value would be $t_{\alpha/2}= 3.182$ . And replacing we got:

$7-3.182 \frac{13.638}{\sqrt{4}}= -14.698$

$7+3.182 \frac{13.638}{\sqrt{4}}= 28.698$

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2 years ago

Need help with math problem give 5 stars and brain thingy point

Nadusha1986 [10]

Answer:

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2 years ago

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