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2 years ago

If an article was bought for £400 and was sold for £336 what is the loss persentages

Mathematics

2 answers:

Gre4nikov [31]2 years ago

8 0

Answer:

Hey mate!

Here is your answer > >

C.P of an article=Rs.400

S.P.of an article=Rs.336

C.P.> S.P., there is a loss

Loss=C.P.-S.P.

=> Loss=400-336

=Rs.64

Loss%=Loss/C.P.×100

=64/400×100

=16%

Hope it helps!

Thankyou ☆ ☆

SpyIntel [72]2 years ago

4 0

Answer: itll be 64

Step-by-step explanation:

dhuiudiSBUVFPVFV WHO CARES WHAT I PUT INHERE

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Answer:

x=6

Step-by-step explanation:

A midpoint is the middle point of a line segment, therefore it is equal distances from both ends of the segment.

This means that PQ and QR have the same length. So all we have to do is set each value equal to each other, and then solve for X.

$3x+14=7x-10\\3x+24=7x\\24-4x\\x=6$

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Can someone help me please?

Elena-2011 [213]

<h3>Answer: 4368 square feet</h3>

======================================================

Explanation:

Check out the diagram below

I drew a rectangle with dimensions 56 ft by 78 ft.

Then I broke up the 56 into 50+6, and I broke up the 78 into 70+8

The reason for this is because it's fairly easy to multiply the areas of each smaller rectangle at this point

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As a way to check, using your calculator shows that 56*78 = 4368

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2 years ago

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

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Step-by-step explanation:

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