Answer: 0.87400mg of caffeine.
Step-by-step explanation:
You have
N(t)=N0(e^−rt)(1)
as a general Exponential decay equation where N0 is the amount at t=0, N(t) is the amount remaining at time t and r is the exponential decay constant. You're specifically given that after 10 hours, the decay factor is 0.2601, i.e.,
N(10)/N(0)=N0(e^−10r)/N0(e^0)= e^−10r=0.2601 . .(2)
Taking the last 2 parts of (2) to the power of 0.1t gives
e^−rt=0.2601^.1t . .(3)
This means that
N(t)=N0(e^−rt)=N0(0.2601^.1t). .(4)
Also,
N(2.56)N(1.56)=N0(0.2601.1(2.56))N0(0.2601.1(1.56))=0.2601.1(2.56−1.56)=0.2601^.1
= 0.87400mg of caffeine.
8-10=-2
-2+5=3
3+7=10
10-(-20)=-10
Final score is -10 points
Answer:
k = 575
Step-by-step explanation:
let d be distance and h time.
Given d varies directly as h then the equation relating them is
d = kh ← k is the constant of variation
To find k use the condition d = 2875, h = 5, then
2875 = 5k ( divide both sides by 5 )
k = 575
The answer is easy
So we need to fund m2NLM
The answer is c
