All categories

2 years ago

The radius of the circle on a basketball court is 6 feet. What are the approximate circumference and area of the circle?

1 answer:

4 0

Circumference formula - 2pi(r)
area formula - pi(r)^2
in both of the formulas r is the radius so

to find circumstance: 2(pi)(6) = 25.68 feet

to find area: pi(6)^2 = 113.04 feet

You might be interested in

Help me with this question please....

kolezko [41]

Answer:

The answer is 2940

Step-by-step explanation:

HAVE A GOOD DAY!

6 0

3 years ago

The sum of three times a number and 28 is 484. Find the number.

Aleksandr [31]

Answer:

152

Step-by-step explanation:

484-28=456

456/3=152

4 0

3 years ago

Read 2 more answers

Can't figure it out!!

Zanzabum

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= \cfrac{1}{x} \qquad 
\begin{cases}
x_1=2\\
x_2=b
\end{cases}\implies \cfrac{f(b)-f(2)}{b-2}=-\cfrac{1}{10}
\\\\\\
\cfrac{\frac{1}{b}-\frac{1}{2}}{b-2}=-\cfrac{1}{10}\implies 
\cfrac{\frac{2-b}{2b}}{b-2}=-\cfrac{1}{10}\implies \cfrac{2-b}{2b}=-\cfrac{b-2}{10}
\\\\\\
$

$\bf \cfrac{2-b}{2b}=\cfrac{2-b}{10}\implies 20-10b=4b-2b^2\impliedby cross-multiplying
\\\\\\
2b^2-4b-10b+20=0\implies 2b^2-14b+20=0
\\\\\\
b^2-7b+10=0\implies 
(b-2)(b-5)=0\implies b=
\begin{cases}
\boxed{5}\\
2
\end{cases}$

8 0

3 years ago

plz help whats the answer to this question !!! calculate the mass of a gold bar that is 18.00cm long, 9.21cm wide, and 4.45cm hi

erik [133]

We have to find the mass of the gold bar.

We have gold bar in the shape of a rectangular prism.

The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.

First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:

Volume of the gold bar $= length \times width\times height$

Plugging the values in the equation we get,

Volume of the gold bar $=18.00 \times 9.21 \times 4.45= 737.721cm^3$

Now that we have the volume we can find the mass by using the formula,

$Mass= density \times volume$

The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:

$Mass = 19.32\times 737.721=14252.769$ grams

So, the mass of the gold bar is 14252.769 grams

7 0

3 years ago

Luis purchases a collectible model car from a dealer. The dealer advises him that the car’s value (The car value is $75 now) wil

serious [3.7K]

Judging by the question I generated the equation y=75(1.09^x)
x is the amount of years.
So the equation you should get for 10 years is y=75(1.09^10)
The answer you get should get is $177.55

4 0

3 years ago

Read 2 more answers