In Harold’s class, there are 7 boys for every 6 girls. Identify three equivalent ratios to compare boys to girls.

2 answers:

5 0

Answer: The ratio of 6 /7 represent the number of boys to the number of girls in one classroom. You are given a total number of boys and girls.

So, your ratio has to represent how many boys to the total number of boys and girls in one classroom, or 13.

The proportion becomes, 6 / 13 = x / 78.

Cross multiply getting, 13 * x = 6 * 78

Divide by 13 to solve for x, or x = 36.

There are 36 boys in all of the classrooms and 42 girls in all of the classrooms.

The ratio of boys to girls in all of the classrooms is 36 / 42, or 6 / 7.

alisha [4.7K]3 years ago

5 0

Answer:

7:6

14:12

21:18

Step-by-step explanation:

7:6

14:12

21: 18

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In general, the exponential growth function is given by the formula below

$f(x)=a(1+r)^x$

Where a and r are constants, and x is the number of time intervals.

In our case, n=0 for 1960; therefore, 1968 is n=8,

$\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}$

And 1976 is n=16

$\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}$

Solve the two equations simultaneously, as shown below

$\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}$

Solving for a,