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tigry1 [53]
3 years ago
10

Triangle ABC has vertices at A(−3, 4), B(4, −2), C(8, 3). The triangle translates 2 units up and 1 unit right. Which rule repres

ents the translation? After the translation, what are the coordinates of vertex A?
Mathematics
1 answer:
Nataly [62]3 years ago
4 0

Answer:

The translation statement is given by:

(x,y)\rightarrow (x+1,y+2)

After the translation, the coordinates of vertex A is (-2,6).

Step-by-step explanation:

Given :

Vertices of a triangle ABC are:

A(−3, 4), B(4, −2), C(8, 3)

The triangle is translated 2 units up and 1 unit right.

To find the co-ordinates of point A after translation.

Translation rules.

For shift of c units up, the translation is given as:

(x,y)\rightarrow (x,y+c)

For shift of k units right, the translation is given as:

(x,y)\rightarrow (x+k,y)

So, it says the triangles is translated 2 units up and 1 unit right.

The translation statement is given by:

(x,y)\rightarrow (x+1,y+2)

So, co-ordinates of point A after translation is given by :

(-3,4)\rightarrow (-3+1,4+2)=(-2,6)

After the translation, the coordinates of vertex A is (-2,6).

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Answer:

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Step-by-step explanation:

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Answer:

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Explination:

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1 (2+1) = 3

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Answer:

option 4.

16 square units

Step-by-step explanation:

as we do not have the measures of the sides, but if the points of the vertices with Pythagoras we can calculate the sides.

P = (2 , 4)

S = (4 , 2)

we have to subtract the values ​​of p from s

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c1: leg 1

c2: leg 2

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R = (8 , 6)

SR = (8-4  ,  6-2)

SR = (4 , 4)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

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SR^2 = 4^2 + 4^2

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