Answer:
m=0.833333
Step-by-step explanation:
(1/16)−3m+1=64
log((1/16)−3m+1)=log(64)
(Take log of both sides)
(−3m+1)*(log(1/16))=log(64)
−3m+1=log(64)
log(1/16)
−3m+1=−1.5
−3m+1−1=−1.5−1
(Subtract 1 from both sides)
−3m=−2.5
−3m
−3
=
−2.5
−3
(Divide both sides by -3)
Answer:
8
Step-by-step explanation:
first, 70-79 have 3 students
then 80-89 have 5 students
Answer: 5/36
Step-by-step explanation:
There are 3 ways to do this
Get a 1 and a 5
Get a 2 and a 4
Or get two 3's.
There are two ways to get a 1 and a 5
1 first and 5 second or
5 first and 1 second
The same goes for the 2 and the 4, but NOT for the two 3s.
We have 5 ways to get a sum of 6
What is the probability of one of them happening?
1/6 x 1/6 = 1/36
1/36 chance of one occuring
1/36 x 5 = 5/36 chance of getting a sum of 6 (as there are 5 ways to do so)
Answer:
what is the question
Step-by-step explanation:
