Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height
b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²
Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²
data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft
(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.
Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³
Answer: ≈202.3 ft³
He would earn <span>$40.95 in that amount of time
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Answer:
Step-by-step explanation:
Δ = 
VΔ = 4 * 8 = 32
a = (- 4 ± 32) * 
a' = 7/2
a''= 9/2
Answer:
80
Step-by-step explanation:
that would be the area of the YARD the fence is surround area is width times length.
if they are really asking the area of the fence itself there isnt enough info here. (I think)
