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AveGali [126]
4 years ago
10

the lengths of two sides of a right triangle are 5 inches and 8 inches. what is the difference between the two possible lengths

of the third side of the triangle?​
Mathematics
1 answer:
horsena [70]4 years ago
5 0

Answer:

3.2 inches!!!!!!

Step-by-step explanation:

Your welcome!

You might be interested in
The pair of points (-4, y) and (5, 7) lie on a line with slope . What is the value of y? You must show all of your work to recei
Svetach [21]

The slope of a line is given by the ratio of the rise to the run of the line.

The value of, y is <u>4</u>

Reasons:

The given points on the line are; (-4, y), and (5, 7)

The slope of the line, = \dfrac{1}{3}

Required:

To find the value of <em>y</em>

<em />

Solution:

The formula for the slope is given as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Where;

(x₁, y₁) = (-4, y)

(x₂, y₂) = (5, 7)

Which gives;

Slope, \, m =\dfrac{7-y}{5-(-4)} = \dfrac{7-y}{5+4} =\dfrac{1}{3}

3·(7 - y) = 1·(5 + 4) = 9

21 - 3·y = 9

3·y = 21 - 9 = 12

y = \dfrac{12}{3} = 4

The value of, y = <u>4</u>

Learn more here:

brainly.com/question/1617757

8 0
3 years ago
As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.10.
Margaret [11]

Answer:

Question 1 ) Difference of Volume = 112.25 cm³

Question 2) Volume = 6400π feet³

Step-by-step explanation:

<h3>As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.10. If the cans are currently 12 cm tall, 6 cm in diameter, and have a volume of 339.12 cm3, how much more will the new cans hold? Use 3.14 for π and round your answer to the nearest hundredth.</h3>

Diameter = 6 cm

Radius = 3 cm

Height = 12 cm

If we increase the dimension by 1.10, new dimesnions are:

Radius = 3 · 1.1 = 3.3 cm

Height = 12 · 1.1 = 13.2 cm

Volume = (Area)(Height) = (πr²)(Height)

Volume = (π)(3.3²)(13.2)

Volume = 451.37 cm³

Difference of Volume = 451.37 cm³ - 339.12 cm³

Difference of Volume = 112.25 cm³

<h3>The circumference of a redwood tree trunk is 16π ft, and it is 100 ft tall. What is the approximate volume of the redwood tree trunk? </h3>

Circumference = 2πr = 16π = 2π(8) feet

Radius = 8 feet

Volume = Volume = (Area)(Height) = (πr²)(Height)

Volume = (π)((8²)(100)

Volume = 6400π feet³

5 0
3 years ago
How many solutions does this linear system have y=2x-5. -8-4y=20​
ollegr [7]

Answer:

One solution

Step-by-step explanation:

y = 2x – 5. –8x – 4y = –20. one solution: (–2.5, 0)

4 0
3 years ago
Calculate the perimeter of the following rectangle:
Oksi-84 [34.3K]

Answer:

i realy dont know sorry

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How to calculate confidence interval with standard deviation?
barxatty [35]
Confidence interval of a standard deviation

A confidence interval can be computed for almost any value computed from a sample of data, including the standard deviation.

The SD of a sample is not the same as the SD of the population

It is straightforward to calculate the standard deviation from a sample of values. But how accurate is that standard deviation? Just by chance you may have happened to obtain data that are closely bunched together, making the SD low. Or you may have randomly obtained values that are far more scattered than the overall population, making the SD high. The SD of your sample does not equal, and may be quite far from, the SD of the population.

Confidence intervals are not just for means

Confidence intervals are most often computed for a mean. But the idea of a confidence interval is very general, and you can express the precision of any computed value as a 95% confidence interval (CI). Another example is a confidence interval of a best-fit value from regression, for example a confidence interval of a slope.

The 95% CI of the SD

<span>The sample SD is just a value you compute from a sample of data. It's not done often, but it is certainly possible to compute a CI for a SD. GraphPad Prism does not do this calculation, but a free GraphPad QuickCalc does.</span>

Interpreting the CI of the SD is straightforward. If you assume that your data were randomly and independently sampled from a Gaussian distribution, you can be 95% sure that the CI  contains the true population SD.

How wide is the CI of the SD? Of course the answer depends on sample size (n). With small samples, the interval is quite wide as shown in the table below.

n        95% CI of SD

2        0.45*SD to 31.9*SD

3        0.52*SD to 6.29*SD

5        0.60*SD to 2.87*SD

10        0.69*SD to 1.83*SD

25        0.78*SD to 1.39*SD

50        0.84*SD to 1.25*SD

100        0.88*SD to 1.16*SD

500        0.94*SD to 1.07*SD

1000        0.96*SD to 1.05*SD

Example

Data: 23, 31, 25, 30, 27

Mean:        27.2

SD:        3.35

The sample standard deviation computed from the five values  is 3.35. But the true standard deviation of the population from which the values were sampled might be quite different. From the n=5 row of the table, the 95% confidence interval extends from 0.60 times the SD to 2.87 times the SD. Thus the 95% confidence interval ranges from  0.60*3.35 to 2.87*3.35,  from 2.01 to 9.62. When you compute a SD from only five values, the upper 95% confidence limit for the SD is almost five times the lower limit.

Most people are surprised that small samples define the SD so poorly. Random sampling can have a huge impact with small data sets, resulting in a calculated standard deviation quite far from the true population standard deviation.

Note that the confidence interval is not symmetrical around the computed SD. Why? Since the SD is always a positive number, the lower confidence limit can't be less than zero. This means that the upper confidence interval usually extends further above the sample SD than the lower limit extends below the sample SD. With small samples, this asymmetry is quite noticeable.

Computing the Ci of a SD with Excel

These Excel equations compute the confidence interval of a SD. n is sample size; alpha is 0.05 for 95% confidence, 0.01 for 99% confidence, etc.:

Lower limit: =SD*SQRT((n-1)/CHIINV((alpha/2), n-1))

<span>Upper limit: =SD*SQRT((n-1)/CHIINV(1-(alpha/2), n-1))
</span>

7 0
3 years ago
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