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Pie
3 years ago
6

2. Jules conducted a survey and asked 100

Mathematics
1 answer:
Tanzania [10]3 years ago
3 0
"Positive association" would be the answer.
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Given line segment AB with endpoints A(-1,7) and B(11, -1)<br> Find the length of AB.
ser-zykov [4K]

Step-by-step explanation:

some to check if it correct

6 0
3 years ago
Evaluate the surface integral. S xz ds, s is the part of the plane 2x 2y z = 4 that lies in the first octant
maksim [4K]

The value of the given surface integral is 4.

The given plane intercepts the coordinate axes at (2, 0, 0), (0, 2, 0), and (4, 0, 0). These point are the coordinates of a triangular region that we can parameterize using.

S(u,v)=(1-u)((1-u)(2,0,0)+u(0,2,0)+u(4,0,0)\\S(u,v)=(2(1-u)(1-v),2u(1-v),4v)

<h3>What is the surface integral?</h3>

A surface integral is a generalization of multiple integrals to integration over surfaces. It can be thought of as the double integral analog of the line integral. Given a surface, one may integrate a scalar field over the surface or a vector field.

with 0≤u≤1 and  0≤v≤1. Then the surface element ds  is equivalent to

ds=\||\:\left(s_u\times \:\:S_v\right)||dudv=12\left(1-v\right)dudv

The surface integral is then

\int \:\int \:_Sxzds=12\int _0^1\:\int _0^1\:\left(2\left(1-u\right)\left(1-v\right),2u\left(1-v\right),4v\right)dvdu=4

Therefore the value of the given surface integral is 4.

To learn more about the integral visit:

brainly.com/question/14295614

#SPJ2

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B4%5Csqrt%7B5%7D%7D%7B3%5Csqrt%7B2%7D%20%7D" id="TexFormula1" title="\frac{4\sqrt{5}}
kykrilka [37]

Step-by-step explanation:

= \frac{4 \sqrt{5} }{3 \sqrt{2} }

Calculate the expression...

= \frac{4\sqrt{10} }{6}

Reduce the fraction..

= \frac{2 \sqrt{10} }{3}

7 0
3 years ago
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3 years ago
ANSWER 30 a and b PLEASE I REALLY NEED HELP! THANK YOU, BEST ANSWER GETS BRAINLIEST AS USUAL!
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