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Anvisha [2.4K]
2 years ago
12

{3\sqrt{2} }" alt="\frac{4\sqrt{5}}{3\sqrt{2} }" align="absmiddle" class="latex-formula">
Please solve with steps
Mathematics
2 answers:
kykrilka [37]2 years ago
7 0

Step-by-step explanation:

= \frac{4 \sqrt{5} }{3 \sqrt{2} }

Calculate the expression...

= \frac{4\sqrt{10} }{6}

Reduce the fraction..

= \frac{2 \sqrt{10} }{3}

Contact [7]2 years ago
7 0

Answer -

  • Given expression -

\frac{4 \sqrt{5} }{3 \sqrt{2} }  \\

<u>we're</u><u> </u><u>required</u><u> </u><u>to </u><u>rationalise</u><u> </u><u>the </u><u>expression</u><u> </u><u>!</u>

<u>therefore</u><u> </u><u>,</u><u> </u><u>we'll</u><u> </u><u>be </u><u>rationalising </u><u>the </u><u>denominator.</u>

\frac{4 \sqrt{5} }{3 \sqrt{2} }  \times  \frac{3 \sqrt{2} }{3 \sqrt{2} }  =  \frac{12 \sqrt{10} }{18}  \\  \\ \implies \:  \frac{\cancel6(2 \sqrt{10}) }{\cancel{18} } \\  \\ \implies \:  \frac{2 \sqrt{10} }{3}

hope this helps !

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121=112+3k
minus 112 both sides
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What is the area of a 45 degree sector of a circle with a radius of 12 in.
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a circle of radius 12 inches

and \theta = 45°

now we know that ,

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let's now plug in the values of radius and theta as 12 inches and 45° respectively ,

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6 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%20%7Bx%7D%5E%7B2%7D%20%20%3D%20%20%7B16%7D%5E%7Bx%7D%20" id="TexFormula1" title=" {x}^{2}
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3 years ago
Help please <br> Right angle triangle
baherus [9]

Answer:

h ≈ 11.9

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Since the triangle is right we can use the cosine ratio to find h

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Multiply both sides by 13

13 × cos24° = h

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8 0
3 years ago
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Answer:

a. Probability = 0.15

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Step-by-step explanation:

Given

P(Bedroom) = 0.4

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This is calculated as:

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6 0
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