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3 years ago

HELP ASAP!!!!!!! NO LINKS OR FAKE ANSWERS OR I WILL REPORT U!

Mathematics

1 answer:

Semmy [17]3 years ago

5 0

Answer:

Step-by-step explanation:

54, $1\frac{2}{3}$ , 1, 0.5, 0.03, 0, - 1, - $1\frac{3}{4}$ , - 4, - 103

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I need the product of a^4xa^6

emmainna [20.7K]

A^4 * a^6

exponent rule : x^y * x^z = x^(y + z)

so, a^4 * a^6 = a^(4 + 6) = a^10

3 0

3 years ago

Find the slope of the line passing through the pairs of points and describe the line as rising, falling, horizontal or vertical.

Anna [14]

Answer:

$a.\ m=2,\ \text{the line is rising}\\\\b.\ m=-\dfrac{5}{4},\ \text{the line is falling}\\\\c.\ m=0,\ \text{the line is horizontal}\\\\d.\ m\ is\ unde fined,\ \text{the line is vertical}$

Step-by-step explanation:

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

m > 0, then a line is rising

m < 0, then a line is falling

m = 0, then a line is horizontal

m is undefined, then a line is vertical

(2, 1) and (4, 5)

$m=\dfrac{5-1}{4-2}=\dfrac{4}{2}=2>0\to\text{rising}$

(-1, 0) and (3, -5)

$m=\dfrac{-5-0}{3-(-1)}=\dfrac{-5}{4}=-\dfrac{5}{4}$

(2, 1) and (-3, 1)

$m=\dfrac{1-1}{-3-2}=\dfrac{0}{-5}=0\to\text{horizontal}$

(-1, 2) and (-1, -5)

$m=\dfrac{-5-2}{-1-(-1))}=\dfrac{-7}{0}\ \text{UNDEFINED}\to\text{vertical}$

7 0

3 years ago

One astronomical unit is about 93,000,000 miles. At 20,000 miles per hour how many astronomical units can Orion travel? ( Orion

uranmaximum [27]

Answer:

$2.15\times 10^{-4}\ AU$

Step-by-step explanation:

Given that:-

The speed of the orion= 20,000 miles per hour

Time = 1 hour ( From source )

Thus,

Distance = Speed * Time = 20,000*1 miles = 20,000 miles

Thus, in 1 hour, the orion can travel 20,000 miles

Also,

93,000,000 miles = 1 astronomical unit

1 mile = 1/93,000,000 astronomical unit

20,000 miles = (1/93,000,000)*20,000 astronomical unit

<u>The orion can travel $2.15\times 10^{-4}$ AU in one hour.</u>

4 0

3 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is: