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1 year ago

Corrine wrote temperatures in degrees Celsius and the equivalent temperatures in degrees Fahrenheit.

1 answer:

6 0

Draw a graph of the temperatures; if the points form a straight line, then the temperatures vary directly , Option B is the correct answer.

<h3>What is Direct Variation ?</h3>

When a quantity of one variable is increased and the value of the other also increases then they are said to be in direct variation.

For the data to be in direct variation

Draw a graph of the temperatures; if the points form a straight line, then the temperatures vary directly.

The points in any linear equation can only fluctuate directly, therefore all points will lie on the same line.

Option B is the correct answer.

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Step-by-step explanation:

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The result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

<h3>How to evaluate the expression?</h3>

The expression is given as:

$\sin^2(\theta) * (1 + \cos(\theta))$

Express $\sin^2(\theta)$ as $1 - \cos^2(\theta)$ .

So, we have:

$\sin^2(\theta) * (1 + \cos(\theta)) = (1- \cos^2(\theta)) * (1 + \cos(\theta))$

Open the bracket

$\sin^2(\theta) * (1 + \cos(\theta)) = 1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Express 1 as cos°(Ф)

$\sin^2(\theta) * (1 + \cos(\theta)) = cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Hence, the result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

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2 years ago

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Harlamova29_29 [7]

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What is Statistical inference?

rjkz [21]

Answer:

<em>Definition 1: The theory, methods, and practice of forming judgments about the parameters of a population and the reliability of statistical relationships, typically on the basis of random sampling.</em>

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Step-by-step explanation:

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