Combine the like terms.<br> 7W-W+3

I need the explanation too !

lubasha [3.4K]

<h2>Step-by-step explanation:</h2>

$- 2y + x + 3 - 5x + 7 + 4y$

$= - 2y + 4y + x - 5x + 7 + 3$

$= 2y - 4x + 10$

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6 0

3 years ago

Read 2 more answers

As accounts manager in your company, you classify 75% of your customers as "good credit" and the rest as "risky credit" dependin

Elena-2011 [213]

Answer:

The percentage of overdue accounts are held by customers in the "risky credit" category is 62.5%

Step-by-step explanation:

Customers in the "risky" category (25% of total accounts) allow their accounts to go overdue 50% of the time on average.

That means that on average, 12.5% of total accounts is overdue.

0.25*0.50 = 0.125

In the "good credit" category only 10% goes overdue. That means 7,5% of total accounts goes overdue in this category.

0.75*0.10=0.075

The total accounts that go overdue is 0.125+0.075 = 0.200.

The percentage of overdue accounts held by customers in the "risky credit" category is:

0.125/0.200 = 0.625 or 62.5%

4 0

2 years ago

The mean amount purchased by a typical customer at Churchill's Grocery Store is $26.00 with a standard deviation of $6.00. Assum

Vadim26 [7]

Answer:

a) 0.0951

b) 0.8098

c) Between $24.75 and $27.25.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 26, \sigma = 6, n = 62, s = \frac{6}{\sqrt{62}} = 0.762$

(a)

What is the likelihood the sample mean is at least $27.00?

This is 1 subtracted by the pvalue of Z when X = 27. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{27 - 26}{0.762}$

$Z = 1.31$

$Z = 1.31$ has a pvalue of 0.9049

1 - 0.9049 = 0.0951

(b)

What is the likelihood the sample mean is greater than $25.00 but less than $27.00?

This is the pvalue of Z when X = 27 subtracted by the pvalue of Z when X = 25. So

X = 27

$Z = \frac{X - \mu}{s}$

$Z = \frac{27 - 26}{0.762}$

$Z = 1.31$

$Z = 1.31$ has a pvalue of 0.9049

X = 25

$Z = \frac{X - \mu}{s}$

$Z = \frac{25 - 26}{0.762}$

$Z = -1.31$

$Z = -1.31$ has a pvalue of 0.0951

0.9049 - 0.0951 = 0.8098

c)Within what limits will 90 percent of the sample means occur?

50 - 90/2 = 5

50 + 90/2 = 95

Between the 5th and the 95th percentile.

5th percentile

X when Z has a pvalue of 0.05. So X when Z = -1.645

$Z = \frac{X - \mu}{s}$

$-1.645 = \frac{X - 26}{0.762}$

$X - 26 = -1.645*0.762$

$X = 24.75$

95th percentile

X when Z has a pvalue of 0.95. So X when Z = 1.645

$Z = \frac{X - \mu}{s}$

$1.645 = \frac{X - 26}{0.762}$

$X - 26 = 1.645*0.762$

$X = 27.25$

Between $24.75 and $27.25.

3 0

3 years ago

Prove the identity (n-5)^2 - (6n-35)=(n-10)(n-6)

elena-14-01-66 [18.8K]

Answer:

(n-5)^2 - (6n-35)=(n-10)(n-6)

-----------

n²-10n+25-6n+35 =
n²-16+60 = n²- 10n - 6n + 60 =
n(n-10) - 6(n-10) =
(n-10)(n-6)

7 0

3 years ago

A. Going 20 miles per hour over the speed limit will result in a fine of $ 2

Zina [86]

Assuming that the cost of the fine is proportionate per each 20mph increase, then a 40mph speeding ticket should be $4, and if they received a fine of $150 would be a crazy amount of speed, is there something you did not attach?

5 0

2 years ago

Combine the like terms. 7W-W+3