All categories

3 years ago

Combine the like terms. 7W-W+3

Mathematics

1 answer:

Bess [88]3 years ago

7 0

The like terms are 7w and -w, so we can collect them to get:

6w+3

Hope this helps!! :)

You might be interested in

What is the probability of flipping a coin 10 times and getting heads four times Rania answer to the nearest 10th of a percent

EleoNora [17]

Answer: 0.205

Step-by-step explanation:

The probability in one flip is equal to 0.5.

Now, if we do 10 flips, we want 4 times that the coin ends in heads and the other 6 times it must end in tails, so the probability is:

0.5^4*0.5^6 = 0.5^10

Now, this is the case where in the first 4 flips we get heads and in the other 6 we get tails, but we have other ways to get only 4 heads (for example in the last 4 flips, 2 at the beginning and 2 at the end, etc)

So we also need to calculate all the possible permutations of 4 heads in 10 flips. this is:

C = 10!/(10 - 4)!*4! = (10*9*8*7)/(4*3*2*1) = 210

So the probability that we are looking for is:

P = (0.5^10)*210 = 0.205

4 0

4 years ago

A scientist is studying red maple tree growth in a state park. She measured the trunk diameters of a sample of trees in the same

Genrish500 [490]

The answer will beee (A.22)

3 0

3 years ago

Read 2 more answers

The adult height of a man is about 1.19 times his height at age 12. Miguel is 1.5 m tall at 12 years of age. What would his pred

jarptica [38.1K]

Answer: 3.285?

I just multiplied 1.5 and 1.19, then added the product and his height at the age of 12 so, therefore i got 3.285 as a answer

6 0

3 years ago

Identify the transformation

wolverine [178]

Answer:8pts

Step-by-step explanation:

5 0

4 years ago

Which expression is equivalent to the expression below? StartFraction m + 3 Over m squared minus 16 EndFraction divided by Start

Kamila [148]

Option B: $\frac{1}{(m-4)(m-3)}$ is the correct answer.

Explanation:

The given expression is $\frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}$

Simplifying the expression, we have,

$\frac{m+3}{m^{2}-16}\times\frac{m+4}{m^2-9}$

Factor the equations, $m^{2}-16\right$ and $m^{2}-9$ ,we get,

$m^{2}-16\right=m^{2}-4^{2}=(m+4)(m-4)$

$m^{2}-9=m^{2}-3^2=(m+3)(m-3)$

Substituting these factored expressions in the above expression, we have,

$\frac{m+3}{(m+4)(m-4)}\times\frac{m+4}{(m+3)(m-3)}$

Cancelling the common terms $m+3$ and $m+4$ , we get,

$\frac{1}{(m-4)(m-3)}$

Thus, the expression equivalent to $\frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}$ is $\frac{1}{(m-4)(m-3)}$

Hence, Option B is the correct answer.

3 0

3 years ago

Read 2 more answers