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CaHeK987 [17]
3 years ago
11

Please help ASAP! Classify each angle

Mathematics
1 answer:
coldgirl [10]3 years ago
7 0

Answer:

RLS is a straight angle

RLT is an obtuse angle

TLS is an acute angle

TRL is not an angle

TLU is a straight angle

SLU is an obtuse angle

SLT is an acute angle

ULR is an acute angle

and ULS is an obtuse angle

Step-by-step explanation:

You really just have to look at the angles from either of the straight angles (angles that are 180°) perspective and see of they lean more to make a smaller angle by leaning towards the other end of the angle, or a large one by leaning away from the opposite end.

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Find the 52nd term in the following sequence.<br><br> -31, -41, -51, -61,
katrin [286]

Answer:

a_{52} = -541

Step-by-step explanation:

4 0
3 years ago
Please help i don't even where to start<br><br>solve for x​
aliina [53]

The radius is 10, so the diameter is 20. This means the parts of the diameter (the chord through the center P) to the left and right of the vertical chord have lengths 16 and 4, respectively.

Because the horizontal chord is a diameter, the vertical chord is cut in half, so its parts above and below the diameter both have length <em>x</em>.

Now, by the intersecting chord theorem,

16×4 = <em>x</em> × <em>x</em>

or

<em>x</em> ² = 64

so that

<em>x</em> = 8

6 0
3 years ago
How do you find the fraction of 0.35
SOVA2 [1]

Answer:

\frac{7}{20}

Step-by-step explanation:

0.35 is the same as 35/100

which can be simplified to 7/20

4 0
2 years ago
The roots of the equation are 3 + 8i and 3 – 8i.
g100num [7]
Given that the roots of the equation x^2-6x+c=0 are 3+8i and 3-8i, the value of c can be obtained as follows;
taking x=3+8i and substituting it in our equation we get:
(3+8i)^2-6(3+8i)+c=0
-55+48i-18-48i+c=0
collecting the like terms we get:
-55-18+48i-48i+c=0
-73+c=0
c=73
the answer is c=73
3 0
3 years ago
What is the solution to the following system of equations?
kipiarov [429]

Answer:

(0, -6)

Step-by-step explanation:

Given the following systems of linear equations;

3x - 2y = 12 ...... equation 1

16x - 4y = 24 ........ equation 2

We would solve for the solution using the elimination method;

Multiplying eqn 1 by 2, we have;

2 * (3x - 2y = 12)

6x - 4y = 24

16x - 4y = 24

Subtracting the two equations, we have;

(6x - 16x) + (-4y -[-4y]) = (24 - 24)

-10x - 0 = 0

-10x = 0

x = -0/10 = 0

Next, we would find the value of y;

3x - 2y = 12

3(0) - 2y = 12

0 - 2y = 12

-2y = 12

y = -12/2

y = -6

Check:

3x - 2y = 12

3(0) - 2(-6) = 12

0 - (-12) = 12

12 = 12

Note: the options provided for this questions are incorrect or inappropriate.

5 0
3 years ago
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