Use the graph of f(x) to explain the relationship between the real zeros of f(x) and its intercept(s). f(x) has one real zero at
–2 because the graph of the function has an intercept at (0, –2). f(x) has two real zeros at –4 and –2 because the graph of the function has intercepts at (–4, 0) and (0, –2). f(x) has no real zeros because the graph of the function does not pass through (0, 0). f(x) has one real zero at –4 because the graph of the function has an intercept at (–4, 0).
f(x) has one real zero at –4 because the graph of the function has an intercept at (–4, 0).
Step-by-step explanation:
Zeros of a function f(x) are those points where f(x) = 0. Then, zeros coordinates have the form (x1, 0), (x2, 0), et cetera. In the graph, a zero is seen as the interception of f(x) with the x-axis.
So first turn it into an improper fraction, so it would be 7/5×2/1. So once multiplied, your answer will be 14/5. then to express as a decimal, you do 14÷5, which would be 2.8