Answer:
The work done is - 200 μJ.
Step-by-step explanation:
The potential difference between two points M and N is UMN = 100 V. A charge q = -2μC moves from M to N, the work of the electric force is:
Potential difference, V = 100 V
Charge, q = - 2 μC
The potential difference is defined as the amount of work done in bringing a unit positive test charge from one point to another in the electric field.
So, W = q V
W = - 2 μC x 100 V = - 200 μJ
Answer:
If you take a number and 'subtract" it with another number, it means that you take your second number and remove that amount from the first number
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Step-by-step explanation:
tricky, as the sequence does not define the input values.
by we can assume that the corresponding input values are 1, 2, 3, 4, 5, ... as it is usual for a sequence.
in that sense, b is the correct answer.