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Arisa [49]
3 years ago
11

Write an Algebraic expression for the following phrases. K. The sum of a number m and 15 L. 6 more than a number x M. 8 less tha

n N. 27 of a number N. The sum of three consecutive integers 0. The sum two consecutive even integers​

Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0

1:-

\\ \sf\longmapsto m+15

2:-

\\ \sf\longmapsto x+6

3:-

\\ \sf\longmapsto r-8

4:-

\\ \sf\longmapsto \dfrac{3}{4}x=\dfrac{3x}{4}

5:-

\\ \sf\longmapsto n(n-1)(n-2)=n!

6:-

\\ \sf\longmapsto n+(n+2)=2n+2

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Help please
Digiron [165]

Answer:

Option C.

Step-by-step explanation:

Shortest way to solve this question is to find the factors of the given expression.

The given expression is (x² + 13).

Now we have to factorize it.

(x² + 13) = x² + (√13)²

            = x² + [-(i)²√(13)²]  [Since i = √(-1)]

            = x² - (i√13)²

            = (x - i√3)(x + i√3) [Since (a² - b²) = (a + b)(a - b)]

Option C will be the answer.

7 0
2 years ago
A bit hard for me !!!!!
Annette [7]
Where they intersect is (-1,2) hope this helps
4 0
3 years ago
Read 2 more answers
There are 790 cal in 610 ounce bottles of apple juice how many calories are there in one 10 ounce bottle of apple juice
Akimi4 [234]
I would say 18 because 790-610= 180 and 180÷10= 18
7 0
3 years ago
A prize wheel is divided into 12 equally likely spaces labeled 1 to 12.
ikadub [295]

Answer:

Events E and F are independent.

Step-by-step explanation:

E = {multiple of 3}  = {3, 6, 9, 12}

P(E) = 4/12

F = {even number}  = {2, 4, 6, 8. 10, 12}

P(F) = 6/12

E and F = {even and multiple of 3} = {6, 12}

P(E∩F) = 2/12

In order for two events to be independent the following relationship must be true:

P(E)*P(F) = P(E\cap F)

Testing this property:

P(E)*P(F) = \frac{4}{12}*\frac{6}{12}=\frac{24}{144}=\frac{1}{6}    \\P(E\cap F) = \frac{2}{12}=\frac{1}{6} \\P(E)*P(F) = P(E\cap F)

The relationship holds true, thus events E and F are independent.

4 0
3 years ago
Can someone please answer this I don’t understand!
Dovator [93]

The coordinates of X are (5, 11).

Solution:

Given points of the line segment are P(2, 2) and T(7, 17)  

Let X be the point that partitions the directed line segment PT in the ratio 3 : 2

Using section formula, we can find the coordinate of the point that partitions the line segment.

Section formula:

$X(x, y)=\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+n y_{1}}{m+n}\right)

Here, x_{1}=2, y_{1}=2, x_{2}=7, y_{2}=17 and m = 3, n =2

Substitute these in the section formula,

$X(x, y)=\left(\frac{3 \times 7+2 \times 2}{3+2}, \frac{3 \times 17+2 \times 2}{3+2}\right)

            $=\left(\frac{21+4}{5}, \frac{51+4}{5}\right)

           $=\left(\frac{25}{5}, \frac{55}{5}\right)

           =(5, 11)

X(x, y) = (5, 11)

The coordinates of X are (5, 11).

6 0
3 years ago
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