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Minchanka [31]
3 years ago
5

1. What is the solution to 6m – 10 = 22 – 2m?​

Mathematics
1 answer:
kogti [31]3 years ago
5 0

Answer:

4

Step-by-step explanation:

6m- 10= 22-2m

you take like terms.....the ones with an alphabet meets each other and the ones without an alphabet meet each other

6m- 10= 22- 2m

6m+2m = 22 +10

when a minus is crossing the equality sign it becomes plus and when plus is crossing an equality sign it becomes minus....Gotten?

so, lets solve

we will add

8m= 32

we will divide the numbers with the coefficient of the unknown which is 8

8m/8=m

8 divide 8 willl be 1 which is m and not 1m that is wrong in maths.....okay

8 divide 32 is 4

so we have our answer m=4

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zaharov [31]

Row A:   x = 3

y = 2x - 3

y = 2(3) - 3 = 3      This is correct

Row B: x = 5

y = 2x - 3

y = 2(5) - 3 = 7        This is correct

Row C: x = 7

y = 2x - 3

y = 2(7) - 3 = 11      this is correct

Row D: x = 10

y = 2x - 3

y = 2(10) - 3 = 17  THIS IS INCORRECT, SO ROW D

8 0
3 years ago
Please someone help me I don’t understand
Thepotemich [5.8K]

Answer:

Step-by-step explanation:

Remark

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8 0
3 years ago
X^2+11=36<br><br> X^2-25/x+5 =0<br><br> What is the value of x for both
Flura [38]

Answer:

<h2>x = 5</h2>

Step-by-step explanation:

x^2+11=36\qquad\text{subtract 11 from both sides}\\\\x^2=25\to x=\pm\sqrt{25}\\\\x=-5\ or\ x=5\\============================\\\\\dfrac{x^2-25}{x+5}=0\qquad Domain:\ x+5\neq0\to x\neq-5\\\\\dfrac{x^2-25}{x+5}=0\to x^2-25=0\qquad\text{add 25 to both sides}\\\\x^2=25\to x=-5\notin D\ or\ x=5\in D

5 0
3 years ago
Factor completely x2 + 16.<br><br> (x + 4)(x + 4)<br> (x + 4)(x − 4)<br> Prime<br> (x − 4)(x − 4)
Sindrei [870]
It's prime because the constant term is positive and there is no middle term. If it were x^2 - 16, we could use (x+4)(x-4), but because 16 is positive, it cannot be factored
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3 years ago
Please help me with this
Vitek1552 [10]

Answer:

A = 6.2831853071796 in^{2}

Step-by-step explanation:

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3 0
2 years ago
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