Subtract magazine from total:
25 -5 = 20
Divide by number of erasers:
20/4 = 5
Each eraser cost $5
[-100, -99, -98, -97, -96, 95, -94 .... 94, 95, 96, 97, 98, 99, 100]
its all of the whole numbers from -100 to 100 inclusive
Answer:
Part A)
The number of marbles that Su has at the beginning is 
The number of marbles that Bertha has at the beginning is 
Part B)
The number of marbles that Su has at the end is 
The number of marbles that Bertha has at the end is 
Step-by-step explanation:
Let
x------> number of marbles that Su has at the beginning
y------> number of marbles that Bertha has at the beginning
we know that
----> equation A
----> equation B
substitute equation A in equation B



Find the value of x

Part A) How many marbles did they EACH have at the begining?
The number of marbles that Su has at the beginning is 
The number of marbles that Bertha has at the beginning is 
Part B) How many did they EACH have at the end?

so


therefore
The number of marbles that Su has at the end is 
The number of marbles that Bertha has at the end is 
Answer:
1/6
Step-by-step explanation:
P(8) = number of 8's / total = 1/3
Then keeping the card so we have 7 and 9
P(7) = number of 7's / total = 1/2
P(8, keep, 7) = 1/3 * 1/2 = 1/6