Plz help ASAP I will add branliest to the first answer, I need to solve for the letter

Mathematics

2 answers:

harkovskaia [24]3 years ago

6 0

Answer:

6. r=2

8.x=3

Step-by-step explanation:

6. 4r-3=5

4r-3=5 add 3 to both sides

4r=8 divide 4 by both sides

r=2

8. 5x-6=9

5x-6=9 add 6 to both sides

5x=15 divide 5 by both sides

x=3

Nonamiya [84]3 years ago

3 0

Question 6) 4r - 3 = 5
First we need to add 3 to each side.
4r - 3 + 3 = 5 + 3
4r = 8
Then we will divide each side into 4 groups.
4r/4 = 8/4
r = 2

Question 8) 5x - 6 = 9
First we need to add 6 to each side.
5x - 6 + 6 = 9 + 6
5x = 15
Then we will divide each side into 5 groups.
5x/5 = 15/5
x = 3

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3 years ago

Please help!! What is the solution to the quadratic inequality? 6x2≥10+11x

fredd [130]

Answer:

The solution of the inequation $6\cdot x^{2} \geq 10 + 11\cdot x$ is $\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)$ .

Step-by-step explanation:

First of all, let simplify and factorize the resulting polynomial:

$6\cdot x^{2} \geq 10 + 11\cdot x$

$6\cdot x^{2}-11\cdot x -10 \geq 0$

$6\cdot \left(x^{2}-\frac{11}{6}\cdot x -\frac{10}{6} \right)\geq 0$

Roots are found by Quadratic Formula:

$r_{1,2} = \frac{\left[-\left(-\frac{11}{6}\right)\pm \sqrt{\left(-\frac{11}{6} \right)^{2}-4\cdot (1)\cdot \left(-\frac{10}{6} \right)} \right]}{2\cdot (1)}$