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pogonyaev
2 years ago
10

What is the radius of a Ø6.75" circle? 3.375" or 3.750" or 4.375" or 6.750"

Mathematics
1 answer:
zysi [14]2 years ago
4 0

Answer:4.375

Step-by-step explanation:

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What’s the value of x? :/
kolbaska11 [484]

Answer:

x = 27

Step-by-step explanation:

According to congruent chords and arcs theorem, if \overline{XY} \cong \overline{ZY} then \arc{XY} \cong \arc{ZY}.

This means that \arc{XY} = \arc{ZY} = (6x - 20) degrees

Thus:

\arc{XY} + \arc{ZY} + \arc{ZX} = 360 (full circle = 360°)

\arc{XY} = (6x - 20)

\arc{ZY} = (6x - 20)

\arc{ZX} = 76

Plug in the values into the equation

(6x - 20) + (6x - 20) + 76 = 360

6x - 20 + 6x - 20 + 76 = 360

Add like terms

12x + 36 = 360

Subtract 36 on both sides

12x = 360 - 36

12x = 324

Divide both sides by 12

x = 27

8 0
3 years ago
100 points
lbvjy [14]

Answer:

  • 10

Step-by-step explanation:

IQR is the difference between Q3 and Q1

<u>According to the top box plot:</u>

  • Q1 = 4
  • Q3 = 14

<u>The IQR is:</u>

  • IQR = 14 - 4 = 10
4 0
3 years ago
Read 2 more answers
Simplify 6/sqr3+2<br> NEED HELP PLZ!!
mote1985 [20]

Answer:

1.61

Step-by-step explanation:

6/((sqrt3)+2) in a calculator

5 0
3 years ago
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please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me
mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are  equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH=\sqrt{(5-0)^{2}+(1-1)^{2}}=5 and

GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5

Now, mid point of JH=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

=(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)

Mid point of GI=(\frac{5}{2},1)

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

(GI)^{2}=(IJ)^{2}+(JG)^{2}                             (1)

Now, JI=\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20} and GJ=\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}

Substituting these values in (1), we get

5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }

25=20+5

25=25

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5  and HJ=\sqrt{(0-5)^2+(1-1)^2}=5 are equal, thus, GHIJ is a rectangle.

6 0
3 years ago
-4x + 3y = -19<br> -4x - y = -15
Stells [14]

Answer:

x=

−3

4

y+

−19

4

Step-by-step explanation:

8 0
3 years ago
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