2x^2+20x=-38 divide both sides by 2
x^2+10x=-19, halve the linear coefficient, square it, than add that value to both sides of the equation, in this case add (10/2)^2=25...
x^2+10x+25=6 now the left side is a perfect square
(x+5)^2=6 take the square root of both sides
x+5=±√6 subtract 5 from both sides
x=-5±√6 (so answer c.)
The difference between the coefficients 7 and 3 is 4, so one solution is
y = 1, x = -1.
Then the remaining solutions will be of the form
x = -7n-1
y = 3n+1
for some integer n.
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Some of the solutions are (for n=0, -1, -2, 1, 2)
(x, y) = (-1, 1), (6, -2), (13, -5), (-8, 4), (-15, 7)
Answer:
Step-by-step explanation:
We have two fractions and are being asked to subtract them.
7/8 and 1/3 don't have the same denominator, so to do as so, we need to find the LCM of both denominators, multiply them to that, and do the same for the numerators.
So what is the LCM (Least Common Multiple) of 8 and 3?
24.
Therefore :
Answer:
The answer is "After trading, the value would be higher because preferences are diverse".
Step-by-step explanation:
Every person receives a resulting in the possibility from either a grocery shop and gives a value of from 1 to 10. (high). Participants trade these goods with each other for items that prefer to receive randomly but instead assign a second value to the object that finishes after the trade is concluded (1 to 10 again). Its value would've been higher after trading because the total of those before trading choices is unique compared to an exchange sum.
H=6y/5y^(6) -6
hope this helps!!!!!!!!
