3 years ago

Please help and show work

Mathematics

1 answer:

melisa1 [442]3 years ago

4 0

Answer:

first one is simnple cross multiply and divide

12*7=4x

84=4x

x=21

2nd same process but more steps

7x=5(x+8)

7x=5x+40

7x-5x=40

2x=40

x=20

Step-by-step explanation:

You might be interested in

Economic Leading Indicators are based on historical results.<br><br> A.True<br><br> B False

deff fn [24]

I think it’s A I’m not 100 percent sure tho sorry if I’m wrong

4 0

2 years ago

△ABC and △CDE similar right triangles. The coordinates of all the vertices are integers. The relationship between the slope of A

aleksandr82 [10.1K]

hmmmmmmmm......... is it 4?

7 0

3 years ago

Read 2 more answers

I need help with this please help me !

mina [271]

Answer:

The value of x is 13.5 units.

Step-by-step explanation:

You can also apply this formula :

$\frac{a}{ \sin(A) } = \frac{b}{ \sin(B)} = \frac{c}{ \sin(C) }$

So for this question :

$\frac{x}{ \sin(34) } = \frac{11}{ \sin(27) }$

$x = \frac{11}{ \sin(27) } \times \sin(34)$

$x = 13.5 \: units \: (near.tenth)$

6 0

3 years ago

8time-5=12time+1 solve the equation

zalisa [80]

1 * 12 = -40
12 = -40

Since its not possible for twelve to equal negative-forty, than there is no answer for this equation.

5 0

3 years ago

Use the shell method to find the volume of the solid generated by revolving the regions bounded by the curves and lines about th

Nezavi [6.7K]

The two curves intersect when

$-x^2=6-5x\implies x^2-5x+6=(x-3)(x-2)=0\implies x=2,x=3$

The region bounded by $x=0$ and the two curves "ends" with a vertex where $x=2$ . So over the interval [0, 2], we have $6-5x\ge-x^2$ , so that the volume is

$\displaystyle2\pi\int_0^2x(6-5x+x^2)\,\mathrm dx=\boxed{\frac{16\pi}3}$

That is, each cylindrical shell has a radius of $x$ and height $(6-5x)-(-x^2)=6-5x+x^2$ , and their contribution to the total volume is $2\pi$ times the radius and height.

5 0

3 years ago

Please help and show work​

Please help and show work