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user100 [1]
3 years ago
11

Please help with a math problem :/ Please show steps... x^2 -13x = -36

Mathematics
1 answer:
Marianna [84]3 years ago
4 0
X^2 -  13 x = -36 
add 36 to both sides

x^2 - 13x +36 = 0
figure out the factor
(x-4)(x-9) = 0
so (x-4) or (x-9) equals 0
so solution is
x-4=0 add 4 to both sides and get x = 4
x-9=0 add 9 to both sides and get x=9
x={ 4, 9}
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Anna71 [15]

Answer:

n=241

Step-by-step explanation:

We are given

5x^2+nx+48

Let's assume it can be factored as

5x^2+nx+48=(5x-s)(x-r)

now, we can multiply right side

and then we can compare it

5x^2+nx+48=5x^2-5rx-sx+rs

5x^2+nx+48=5x^2-(5r+s)x+rs

now, we can compare coefficients

rs=48

5r+s=-n

n=-(5r+s)

now, we can find all possible factors of 48

and then we can assume possible prime factors of 48

48=-+(1\times 48)

48=-+(2\times 24)

48=-+(3\times 16)

48=-+(4\times 12)

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Since, we have to find the largest value of n

So, we will get consider larger value of r because of 5r

and because n is negative of 5r+s

so, we will both n and r as negative

So, we can assume

r=-48 and s=-1

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The answer is 10x - 1380m + z
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