1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zolol [24]
3 years ago
15

Linda is hosting a candle sale. She has 48 blue candles to put in bags. How many bags can she fill if she puts the same number o

f blue candles in each bag and use them all? List all the possibilities
Mathematics
1 answer:
faust18 [17]3 years ago
6 0
1 bag with 48 candies, 2 with 24 candies, 3 with 16 candies, 4 with 12 candies, 6 with 8 candies, 8 bags with 6 candies, 12 with 4, 16 with 3 each, 24 with 2, and 48 with 1
You might be interested in
Please someone help! You have to make this word problem into an inequality.
labwork [276]

Answer:

the theater needs to sell at least 100 tickets

Step-by-step explanation:

wants to make at least $1000 and they already have $50, so you take the $9.50 per ticket and add that to the $50.

$1000=$9.50t+$50

1000/50=9.5t

950=9.5t

950/9.5=t

t=100

4 0
3 years ago
ABC Bank requires a 20% down payment on all of its home loans. If a house is priced at $105,000, what is the amount of the down
mr_godi [17]
Percentage of down payment that ABC bank requires to be paid = 20%
Price of the house = $10500
Then
Amount of down payment
that needs to be made = (20/100) * 105000
                                     = 21000 dollars
From the above deduction, it can be deduced that the correct option among all the options that are given in the question is the third option or option "C". I hope that this is the answer that has actually come to your desired help.
3 0
3 years ago
Read 2 more answers
A\b=c for bsolve for b and show your steps.show all steps.
Rufina [12.5K]
A/b=c
times both sides by b
A=bc
divide both sides by c
A/c=b
b=A/c
6 0
3 years ago
A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with A random s
wel

Answer:

95%: (3278.354 ; 3270.083)

99% : (3221.646 ; 3278.354)

Step-by-step explanation:

Given :

Sample size, n = 12

Mean, xbar = 3250

Sample standard deviation = √1000

The 95% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.05, df=12-1 = 11 ;

Tcritical at 95% = 2.20

Hence,

Margin of Error = (2.20 * √1000/√12) = 20.083

Confidence interval : 3250 ± 20.083

Lower boundary = 3250 - 20.083 = 3229.917

Upper boundary = 3250 + 20.083 = 3270.083

2.)

The 99% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.01, df=12-1 = 11 ;

Tcritical at 99% = 3.106

Hence,

Margin of Error = (3.106 * √1000/√12) = 28.354

Confidence interval : 3250 ± 28.354

Lower boundary = 3250 - 28.354 = 3221.646

Upper boundary = 3250 + 28.354 = 3278.354

3 0
3 years ago
Need help please asap!
erastovalidia [21]

Answer:

40 degrees

Step-by-step explanation:

90 degrees-50 degrees is equal to 90 degrees.

7 0
2 years ago
Read 2 more answers
Other questions:
  • How do I get the frequency and number where do I start
    9·1 answer
  • Which equation does NOT graph a line? A) y = 5 B) y = -3x3 C) y = 2/3 x D) y = −8x That 3 in b is an exponent btw
    5·1 answer
  • 9,443.2 the 4 in the tens place is ? the value of the 4 in the hundreds place.
    13·1 answer
  • What is the x value for x+7y=10
    5·1 answer
  • Will expand and fill the container into which it is placed
    13·1 answer
  • Red 13 Silver 34 Black 25 White 10 Blue 8
    13·2 answers
  • I have no clue how to solve this and it’s really stressing me out! Can anyone help?
    7·1 answer
  • How do i solve for angle 1 and 2?​
    7·2 answers
  • At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer BLUE edge of the sidewalk is a circle with a RADIUS of 11
    7·1 answer
  • Needs step by step solving. ​
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!