Answer:
Solution given:
A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm
and
base[b]PR=60cm.
perpendicular [P]= QR
<u>by</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>
<u>h²</u><u>=</u><u>p²</u><u>+</u><u>b²</u>
80²=QR²+60²
QR²=80²-60²
QR=
QR=20
=52.9=53cm
<u>QR</u><u>=</u><u>5</u><u>3</u><u>c</u><u>m</u><u>.</u>
To answer the question, let x be the cost of each hamburger, y be the cost of each medium fries, and z be the cost of each medium drink. The equations that are described in the problem are,
(Miller ) 4x + 3y = 18.69
(James) x + 2y + z = 8.66
(Steven) 2x + y + z = 10.27
Solving simultaneously for the values of the variables give x = 3.36, y = 1.75, and z = 1.8.
Thus, each hamburger costs $3.36. Each medium fries cost $1.75, and each drink costs $1.8.
AFC = FC / Quantity printed
<span>So given she prints 1,000 posters: AFC = 250.00/1000 = $0.25 </span>
<span>Given she prints 2,000 posters: AFC = 250.00/2000 = $0.125 </span>
<span>Given she prints 10,000 posters: AFC = 250.00/2000 = $0.025 </span>
<span>ATC = TC / Quantity printed </span>
<span>where TC = FC + Variable C * Quantity printed </span>
<span>If she prints 1000: TC = 250 + 2000*1000 = 2,000,250 </span>
<span>ATC = 2,000,250/1000 = 2000.25 </span>
<span>If she prints 2000: TC = 250 + 1600*2000 = 3,200,250 </span>
<span>ATC = 3,200,250/2000 = 1600.125 </span>
<span>If she prints 10000: TC = 250 + 1600*2000 + 1000*8000 ($1000 for each additional poster after 2000) = 11,200,250 </span>
<span>ATC = 11,200,250/10000 = 1120.025</span>
-3z + 7 = -7 - 10z
Add 10z to both sides
7z + 7 = -7
Subtract 7 from both sides
7z = -14
Divide by 7
Z = -2
Answer:
Gratuity means (18/100)·43 = (18·43)/100 = 774/100 = $7.74;
Step-by-step explanation: