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Dimas [21]
2 years ago
13

What is the difference of the fractions? Use the number line to help find the answer.

Mathematics
1 answer:
rjkz [21]2 years ago
4 0

hope that this answers your problem !

To solve this question, we first need to layout the equation

-2 1/2 -(-1 3/4)

Step 1

-2 1/2-(-1 3/4) ... Equation

Step 2

5/2-(-1 3/4) ... Converted to improper fraction

Step 3

5/2-(-7/4) ... converted to improper fraction

Step 4

5/2--7/4 ... Got rid of parenthesis

Step 5

-3/4 ... Subtract

Answer:

-3/4 ... Answer

So the answer for this problem is C, -3/4

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Simplify the expression. 19m – 4m2 + 4m2
solmaris [256]
I am not sure what does that question mean by simplify. If it means not to solve and just arrange;
You can divide the whole of the equation to m^2

Then you get;
19/m -4 +4

And you can divide the whole equation to 4 then you get;

19/4m -1 +1

You can also write as ;
(1/m * 19/4) - 1 + 1
6 0
3 years ago
Maureen bought cupcakes for her sister's birthday party. 40% of the 95 cupcakes had
Tanzania [10]

Answer:

  • 34 cupcakes

Step-by-step explanation:

<u>We know that:</u>

  • 40/100 x 95

<u>Work:</u>

  • 40/100 x 95
  • => 2/5 x 95
  • => 2 x 17
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Hence, 34 cupcakes had sprinkles.

8 0
2 years ago
Which power has a value of 1?
kogti [31]
X^0=1
5^0=1

1^n=1
answer is 1^4 and 5^0
4 0
3 years ago
If jermeey has 9 apples, and sabrina has 10, how many apples do they have if erica takes 19 of them?
rosijanka [135]

Answer:

0 apples

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
given the points a (-1,2) and (7,14), find the coordinates of the point p on directed line segment ab that partitions ab in the
Vinvika [58]
Check the picture below.

\bf \left. \qquad  \right.\textit{internal division of a line segment}&#10;\\\\\\&#10;a(-1,2)\qquad b(7,14)\qquad&#10;\qquad 1:3&#10;\\\\\\&#10;\cfrac{aP}{Pb} = \cfrac{1}{3}\implies \cfrac{a}{b} = \cfrac{1}{3}\implies 3a=1b\implies 3(-1,2)=1(7,14)&#10;\\\\&#10;-------------------------------\\\\&#10;{ P=\left(\cfrac{\textit{sum of "x" values}}{r1+r2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{r1+r2}\right)}

\bf -------------------------------\\\\&#10;P=\left(\cfrac{(3\cdot -1)+(1\cdot 7)}{1+3}\quad ,\quad \cfrac{(3\cdot 2)+(1\cdot 14)}{1+3}\right)&#10;\\\\\\&#10;P=\left( \cfrac{-3+7}{4}~,~\cfrac{6+14}{4} \right)

3 0
3 years ago
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