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Ivanshal [37]
3 years ago
7

A researcher is selecting lab rats for her experiment. She assigns each rat a number and picks numbers out of a hat while blindf

olded. The pool of rats from which she is drawing participants is composed of the following: 23 male albino rats 21 male spotted rats 35 female albino rats 11 female spotted rats If she reaches into the hat twice, what is the probability of choosing a male albino rat and then either a female albino rat or a male spotted rat
Mathematics
1 answer:
laiz [17]3 years ago
7 0

Answer: \dfrac{76}{89}

Step-by-step explanation:

The pool of rats from which the researcher is drawing participants is composed of the following:

23 male albino rats

21 male spotted rats

35 female albino rats

11 female spotted rats

Total rats = 23+21+35+11 =90

P(male\ albino)=\dfrac{23}{90}

After drawing first rat , total rats remained = 89

P(\text{either a female albino rat or a male spotted rat})=\dfrac{35+21}{89}=\dfrac{76}{89}

The probability of choosing a male albino rat and then either a female albino rat or a male spotted rat = \dfrac{76}{89}

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When a number is decreased by 19%, the result is 66. What is the original number to the nearest tenth?
murzikaleks [220]

Answer:

80

step by step explanation:

when a number is decreased by 19 %, u calculate backwards, making the % to 119% of 66. Hence it becomes 78.54 to be exact, but in the nearest tenth, it becomes 80.

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Step-by-step explanation:

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3 years ago
I'm trying to convert this from standard form to slope intercept form, is my math right?
GarryVolchara [31]
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Minus 2x from both sides gives
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4 years ago
Find the slope of the line passing through the points (-5, 3) and (7, 9) ​
rodikova [14]

\sf{\red{Answer}}

\sf{m =  \frac{1}{2} }

\sf{\purple{Explanation}}

\sf{m =  \frac{y_{2}- y_{1}}{m_{2} - m_{1}} }

\sf{m =  \frac{9- 3}{7- ( - 5)} }

\sf{m =  \frac{6}{7 +  5} }

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2 years ago
−4x+7y+5=0<br> x−3y=−5<br> ​ <br><br> How many solutions does the system have?
xeze [42]

   

Solution:  

Using Substitution Method:

-4x+7y=-5   (Equation 1)

x-3y=-5       (Equation 2)

get the value of x from Equation 2

x=3y-5     (Equation 3)  

Put the value of x from Equation 3 in Equation 1

-4(3y-5)+7y=-5

-4(3y)+20+7y=-5

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-5y=-25

Negative sign on both sides cancels each other

y=25/5

y=5

Putting value of y in equation 3

x=3(5)-5

x=15-5

x=10

Therefore,   [x,y]=[10,5]

Using Elimination Method

-4x+7y=-5   (Equation 1)

x-3y=-5       (Equation 2)

Multiply equation 2 with -4 in order to eliminate the x term

-4(x-3y)=-5*4

-4x+12y=20     (Equation 3)

Adding Equation 1 and 3

-4x+7y=-5    

-4x+12y=20    

+    -     = -   (Change Of Sign with x and y terms)

-----------------

0x-5y = -25

-5y=-25

y=5  

Substituting y’s value is Equation 1

-4x+7(5)=-5

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-4x=-40

Cancellation of negative sign on both sides

x=40/4

x=10

[x,y]=[10,5]

3 0
3 years ago
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