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skad [1K]
2 years ago
10

A fisherman sold some big fish at $4 each and twice as many small fish at

Mathematics
1 answer:
harina [27]2 years ago
5 0

Answer:

The answer is 12 big fish.

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The sum of 0.8 and 0.04 can be written as a fraction where the numerator and the denominator are both positive integers. When th
Luda [366]

Answer: 0.84 as a fraction is 84/100

Greatest common factor is 4

Resulting fraction is 21/25

Addition of numerator and denominator of the resulting fraction is 46

Step-by-step explanation:

From the question, the sum of 0.8 and 0.04 is written as 0.8 + 0.04 = 0.84

Convert 0.84 to fraction = 84/100

The numerator and denominator in 84/100 are both positive integers.

The greatest common factor to the numerator and denominator is 4

Divide 84 by 4 = 21

Divide 100 by 4 = 25

Therefore, the resulting fraction is 21/25

Addition of 21 and 25 equals 46.

I hope this helps.

7 0
2 years ago
Select all of the following that are quadratic equations.
goldenfox [79]

Answer:

1. x² + 3x - 5 = 0

2. x² - x = 3 x + 7

4. 7x² + 14x = 0

Step-by-step explanation:

A Quadratic equation takes the form;

ax² + bx + c = 0

a, b, c are constants and a cannot be 0.

Options 1 fits this;

x² + 3x - 5 = 0

Option 2 fits this as well;

x² - x = 3 x + 7  

x² -x - 3x - 7 = 0

x² - 4x - 7 = 0

Option 4 fits this as well if c = 0.

7x² + 14x + 0 = 0

8 0
2 years ago
Please help me. I can’t do it
Maslowich

Answer: A) -8

B) - 41

C) - 39

Step-by-step explanation:

6 0
2 years ago
A bag contains 7 blue cards, 4 green cards, 6 red cards, and 8 yellow cards. You randomly choose a card. How many possible outco
Digiron [165]

It is given that the bag contains 7 blue cards, 4 green cards, 6 red cards, and 8 yellow cards. Thus, there are four colors of cards. So, in randomly a card there are just four possible outcomes. The outcomes are:

1. A Blue Card

2. A Green Card

3. A Red Card

4. A Yellow Card

Their probabilities of occurrence will differ but it is a fact that there will be just four possible outcomes.

5 0
3 years ago
Read 2 more answers
A group of 2n people, consisting of n men and n women, are to be independently distributed among m rooms. Each woman chooses roo
vfiekz [6]

Step-by-step explanation:

Assume that

X_i = \left \{ {{1, If , Ith, room, has,exactly, 1,man, and , 1,woman } \atop {0, othewise} \right.

hence,

x = x_1 + x_2+....+x_m

now,

E(x) = E(x_1+x_2+---+x_m)\\\\E(x)=E(x_1)+E(x_2)+---+E(x_m)

attached below is the complete solution

7 0
3 years ago
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